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Liono4ka [1.6K]
3 years ago
7

How do you find the speed of an electromagnetic wave? Multiply the wavelength by the frequency. Dvide the frequency by the wavel

ength. Add the wavelength plus the frequency. Divide the wavelength by the frequency.
Physics
1 answer:
Leokris [45]3 years ago
8 0

Answer:

Multiply the wavelength by the frequency.

Explanation:

The velocity of a wave is the frequency times the wavelength.

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6. What is ductility?​
gavmur [86]

Answer:

Explanation:

Best to look it up for better results. The measure of a metals ability to withstand tension or stress to it. Like when when metal is being pulled apart it would be the distance it's being pulled.

6 0
3 years ago
Read 2 more answers
awhite billiard ball with mass mw = 1.47 kg is moving directly to the right with a speed of v = 3.01 m/s and collides elasticall
pochemuha

Answer:

speed of white ball is 1.13 m/s and speed of black ball is 2.78 m/s

initial kinetic energy = final kinetic energy

KE = 6.66 J

Explanation:

Since there is no external force on the system of two balls so here total momentum of two balls initially must be equal to the total momentum of two balls after collision

So we will have

momentum conservation along x direction

m_1v_{1i} + m_2v_{2i} = m_1v_{1x} + m_2v_{2x}

now plug in all values in it

1.47 \times 3.01 + 0 = 1.47 v_1cos68 + 1.47 v_2cos22

so we have

3.01 = 0.375v_1 + 0.927v_2

similarly in Y direction we have

m_1v_{1i} + m_2v_{2i} = m_1v_{1y} + m_2v_{2y}

now plug in all values in it

0 + 0 = 1.47 v_1sin68 - 1.47 v_2sin22

so we have

0 = 0.927v_1 - 0.375v_2

v_2 = 2.47 v_1

now from 1st equation we have

3.01 = 0.375 v_1 + 0.927(2.47 v_1)

v_1 = 1.13 m/s

v_2 = 2.78 m/s

so speed of white ball is 1.13 m/s and speed of black ball is 2.78 m/s

Also we know that since this is an elastic collision so here kinetic energy is always conserved to

initial kinetic energy = final kinetic energy

KE = \frac{1}{2}(1.47)(3.01^2)

KE = 6.66 J

5 0
4 years ago
A deuteron, 21H, is the nucleus of a hydrogen isotope and consists of one proton and one neutron. The plasma of deuterons in a n
Naddik [55]

Answer:

1917723.40119 m/s

Explanation:

m = Mass of deuteron = (1.637+1.675)\times 10^{-27}=3.312\times 10^{-27}

k = Boltzmann constant = 1.381\times 10^{-23}\ J/K

T = Temperature = 2.94\times 10^8\ K

RMS velocity is given by

V_r=\sqrt{\dfrac{3kT}{m}}\\\Rightarrow V_r=\sqrt{\dfrac{3\times 1.381\times 10^{-23}\times 2.94\times 10^8}{3.312\times 10^{-27}}}\\\Rightarrow V_r=1917723.40119\ m/s

The RMS velocity of the deutrons is 1917723.40119 m/s

8 0
3 years ago
A slender rod is 90.0 cm long and has mass 0.120 kg. A small 0.0200 kg sphere is welded to one end of the rod, and a small 0.080
deff fn [24]

Answer:

Speed of 0.08 kg mass when it will reach to the bottom position is 1.94 m/s

Explanation:

When rod is released from rest then due to unbalanced torque about the hinge the system will rotate

Now moment of inertia of the system is given as

I = \frac{ML^2}{12} + \frac{m_1L^2}{4} + \frac{m_2L^2}{4}

now we have

M = 0.120 kg

m_1 = 0.02 kg

m_3 = 0.08 kg

now we have

I = \frac{0.120(0.90)^2}{12} + \frac{0.02(0.90)^2}{4} + \frac{0.08(0.90)^2}{4}

so we have

I = 8.1 \times 10^[-3} + 4.05 \times 10^[-3} + 0.0162

I = 0.02835

now by energy conservation we can say work done by gravity must be equal to change in kinetic energy

so we have

\frac{1}{2}I\omega^2 = m_1g \frac{L}{2} - m_2 g\frac{L}{2}

\frac{1}{2}(0.02835)\omega^2 = (0.08 - 0.02)(9.81)(0.45)

\omega = 4.32 rad/s

Now speed of 0.08 kg mass when it reaches to bottom point is given as

v = \omega \frac{L}{2}

v = 4.32 (0.45)

v = 1.94 m/s

3 0
3 years ago
A pendulum is timed, first for 20 swings and then for
wlad13 [49]

w =  \frac{t(50) - t(20)}{50 - 20}  =  \frac{43.2 - 17.4}{50 - 20}

w =  \frac{25.8}{30}  = 0.86 \: sec \: per \: swing

The results may differ due to resistive forces that may be affecting the system by decelerating it or any other external forces that might accelerate it a bit.Or the timing could be a little inaccurate.

3 0
2 years ago
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