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klasskru [66]
3 years ago
15

How many lines of symmetry, if any, exist for trapezoid ABCD?

Mathematics
2 answers:
galben [10]3 years ago
8 0
I think the answer is 1 but I can’t see the picture
xxMikexx [17]3 years ago
3 0

Answer:

No line of symmetry exists.

Step-by-step explanation:

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2x+9=1x-5 what is x?
Vlada [557]

Answer:

2x+9=1x-5

2x-1x=-5-9

x=-14

4 0
1 year ago
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4. Break-Even Analysis
DiKsa [7]

Answer:

x = 1178 games

Step-by-step explanation:

Let the number of games = x

Let the total cost = Tc

Let the total revenue = Tr

Given the following data;

Investment = $10,000

Cost of each game = $1.50

Selling cost = $9.99

Total cost, Tc = (Cost of each game * Number of games) + Investment

Tc = 1.50x + 10000

Total revenue, Tr = Selling cost * Number of games

Tr = 9.99x

Breakeven point is when total cost is equal to total revenue;

Tc = Tr

1.50x + 10000 = 9.99x

9.99x - 1.50x = 10000

8.49x = 10000

x = \frac {10000}{8.49}

x = 1177.86 ≈ 1178 games.

<em>Therefore, the number of games that must be sold before the business breaks even is 1178 games. </em>

4 0
3 years ago
Solve using long division <br> Please
madreJ [45]

1. Solution,\frac{2x^3+4x^2-5}{x+3}:\quad 2x^2-2x+6-\frac{23}{x+3}

Steps:

\mathrm{Divide}\:\frac{2x^3+4x^2-5}{x+3}:\quad \frac{2x^3+4x^2-5}{x+3}=2x^2+\frac{-2x^2-5}{x+3}

\mathrm{Divide}\:\frac{-2x^2-5}{x+3}:\quad \frac{-2x^2-5}{x+3}=-2x+\frac{6x-5}{x+3}

\mathrm{Divide}\:\frac{6x-5}{x+3}:\quad \frac{6x-5}{x+3}=6+\frac{-23}{x+3}

\mathrm{Simplify}, =2x^2-2x+6-\frac{23}{x+3}

\mathrm{The\:Correct\:Answer\:is\:2x^2-2x+6-\frac{23}{x+3}}

2. Solution, \frac{4x^3-2x^2-3}{2x^2-1}:\quad 2x-1+\frac{2x-4}{2x^2-1}

Steps:

\mathrm{Divide}\:\frac{4x^3-2x^2-3}{2x^2-1}:\quad \frac{4x^3-2x^2-3}{2x^2-1}=2x+\frac{-2x^2+2x-3}{2x^2-1}

\mathrm{Divide}\:\frac{-2x^2+2x-3}{2x^2-1}:\quad \frac{-2x^2+2x-3}{2x^2-1}=-1+\frac{2x-4}{2x^2-1}

\mathrm{The\:Correct\:Answer\:is\:2x-1+\frac{2x-4}{2x^2-1}}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

4 0
3 years ago
A square has a perimeter of 32 and one vertex at (6,8). what could be the location of another vertex of this shape?
lukranit [14]

Answer:

6,5

Step-by-step explanation:

8 0
3 years ago
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How do you do answer these math question I got confused
Sladkaya [172]
The first one I THINK is 21 and the second one I THINK is 20. I'm not sure though sorry if I'm wrong
4 0
3 years ago
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