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lianna [129]
3 years ago
12

A positively charged insulating rod is brought close to an object that is suspended by a string. If the object is repelled away

from the rod we can conclude: A) the object is positively charged B) the object is negatively charged C) the object is an insulator D) the object is a conductor E) none of the above Two small charged objects repel each other with a force F when separated by a distance d. If the charge on each object is reduced to one-fourth of its original value and the distance between them is reduced to d/2 the force becomes: A) F/16 B) F/8 C) F/4 D) F/2 E) F
Physics
1 answer:
Trava [24]3 years ago
3 0

Answer

A)   Positively charged two insulating rod are brought closed to an object  they repel each other. It means the Object is positively charged. Because similar charge repel each other.

   The correct answer is Option A.

B) we know force between to charges is calculated using Formula

         F = \dfrac{kQ_1Q_2}{r^2}.......(1)

   form the given condition in the question

          F' = \dfrac{k\dfrac{Q_1}{4}\dfrac{Q_2}{4}}{(\dfrac{r}{2})^2}

          F' = \dfrac{k\dfrac{Q_1}{4}\dfrac{Q_2}{4}}{(\dfrac{r^2}{4})}

          F' = \dfrac{4}{16}\dfrac{kQ_1Q_2}{r^2}

from equation (1)

          F' = \dfrac{F}{4}

hence, the correct answer is Option C.

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At what pressure will the mean free path in room-temperature (20?c) nitrogen be 1.5 m ?
kondaur [170]
In physical chemistry, the mean free path is the average distance between the atoms during collision. Its formula is

 Mean \ free \ path \ = \frac{RT}{ \sqrt{2}  \pi  d^{2} N_{A}P  }

where d is the diameter of the Nitrogen atom (d = 310 x 10^-7 m), Na is Avogadro's number (Na=6.022 x 10^23), R is the gas constant (8.314 J/mol-K), T is the absolute temperature (T= 20 + 273 = 293 K). Substituting the values,

1.5 = \frac{(8.314)(293)}{ \sqrt{2} \pi (310 \ x\ 10^{-7} )^{2} (6.022 \ x\ 10^{23} )P }
P = 6.32 x 10^-13 Pascals
6 0
4 years ago
A 330-km-long high-voltage transmission line 2.00 cm in diameter carries a steady current of 1,110 A. If the conductor is copper
vodka [1.7K]

Answer:

t = 402 years

Explanation:

To find the number of year that electrons take in crossing the complete transmission line, you first calculate the drift speed of the electrons. Then, you use the following formula for the current in a wire:

I=nqv_dA  (1)

n: number of mobile charge carrier per volume = 8.50*10^28 e/m^3

q: charge of the electron = 1.6*10^-19 C

vd: drift velocity of electron in the metal = ?

A: cross sectional area of the wire = π r^2 = π (0.02m/2)^2 = 3.1415*10^-4 m^2

I: current in the wire = 1110 A

You solve the equation (1) for vd:

v_d=\frac{I}{nqA}=\frac{110A}{(8.50*10^{28}m^{-3})(1.6*10^{-19}C)(3.1415*10^{-4}m^2)}\\\\v_d=2.59*10^{-4}m/s

Next, you calculate the time by using the information about the length of the line transmission:

x=v_dt\\\\x=330km=330000m\\\\t=\frac{x}{v_d}=\frac{330000m}{2.59*10^{-4}m/s}=1,270,184,865s\\\\1,270,184,865s*\frac{1\ year}{3,156,107}=402.45\ years

hence, the electrons will take aproximately 402 years in crossing the line of transmission

6 0
3 years ago
0. A 5-kg block of ice is at a temperature of -27 °C. How much heat must be added to the ice to produce 5 kg of liquid water wit
stellarik [79]

Answer:

Q = 2687130 J

Explanation:

m = mass of block of ice = 5 kg

T_{i} = Initial temperature of ice block = - 27 °C

T_{f} = final temperature of water = 35 °C

c_{i} = specific heat of ice = 2108 J/(Kg °C)

L = Latent heat of fusion of ice = 334000 J/kg

c_{w} = specific heat of water = 4186 J/(Kg °C)

Heat added is given as

Q = m c_{i}(0 - T_{i})+ mL + m c_{w}(T_{f} - 0)

Q = (5) (2108)(0 - (-27))+ (5)(334000) + (5) (4186)(35 - 0)

Q = 2687130 J

8 0
3 years ago
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