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Naddika [18.5K]

3 years ago

10

Pluto has a shape that is nearly round,and it orbits the sun,it has five known moons.why is it called a dwarf planet and not a p

lanet?

1 answer:

s2008m [1.1K]3 years ago

8 0

There are three things needed to be classified as a planet.

Pluto meets 2 of the 3.

The one it does not meet is it doesn’t “clear the neighborhood” which means a planet needs to be gravitationally dominant over all objects around it. Meaning smaller bodies ( asteroids) would either combine with the larger body making it bigger or pushing them away ( out of their orbit) so they do not collide with the larger body.

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3 examples of newtrons 2 law

frozen [14]

Explanation:

1) Kicking a ball.

2) Capture the ball by hand.

3) Push a car.

7 0

2 years ago

a 2 kg rabbit starts from rest and its moving at 6 m/s after 3 seconds . what force must the rabbit cause to makes this change i

Alborosie

Gravity pulling it down or the air cd (carbon dioxide)

3 0

2 years ago

Read 2 more answers

Poiseuille's law remains valid as long as the fluid flow is laminar. For sufficiently high speed, however, the flow becomes turb

Ilia_Sergeevich [38]

Answer: 0.471 m/s

Explanation:

We are given the followin equation:

$Re=\frac{D v \rho}{\eta}$ (1)

Where:

$Re$ is the Reynolds Number, which is adimensional and indicates if the flow is laminar or turbulent

When $Re$ we have a laminar flow

When $Re>4000$ we have a turbulent flow

When $2100$ the flow is in the transition region

$D=2R$ is the diameter of the pipe. If the pipe ha a radius $R=8(10)^{-3} m$ its diameter is $D=2(8(10)^{-3} m)=0.016 m$

$v$ is the average speed of the fluid

$\rho=1060 kg/m^{3}$ is the density of the fluid

$\eta=4(10)^{-3} Pa.s$ is the viscosity of the fluid

Isolating $v$ :

$v=\frac{Re \eta}{D \rho}$ (2)

Solving for $Re=2000$

$v=\frac{(2000)(4(10)^{-3} Pa.s)}{(0.016 m)(1060 kg/m^{3})}$ (3)

Finally:

$v=0.471 m/s$

4 0

3 years ago

Explain what a coulomb is and be able to change from electron to coulomb and vice versa

torisob [31]

Answer:

Cuolomb is SI unit of charge

1 e=1.6022E-19 C

1 C = 6.2415E+18 e

Explanation:

Coulomb(C) is the SI unit for measuring electric charge and is given as the product of current and time. To convert Cuolomb to electron, we multiply each cuolomb of charge by 1 C = 6.2415E+18 e while to convert electron into charge, we multiply the electrons by 1e=1.6022E-19 C

4 0

2 years ago

We can compare these two interactions on the basis of impulse (see above), but sometimes, we are more interested in the forces (

kiruha [24]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

$I = 476 \ N \cdot s$

b

$I_1 = 14.21 \ N\cdot s$

c

$F = 20300 \ N$

Explanation:

Considering the first question

From the question we are told that

The force produced is $F = 3400 \ N$

The duration of the punch is $t = 0.14 \ s$

Generally the impulse delivered is mathematically represented as

$I = F * t$

=> $I = 3400 * 0.14$

=> $I = 476 \ N \cdot s$

Considering the second question

The approaching velocity of the ball is $v_b = 45 \ m/s$

The leaving velocity of the ball is $v_l = -53 \ m/s$

The mass of the ball is $m_b = 0.145 \ kg$

Generally the magnitude of the impulse delivered is mathematically represented as

$I_1 = m* v_b - m * v_l$

=> $I_1 = [0.145 * 45] - [0.145 * -53]$

=> $I_1 = 14.21 \ N\cdot s$

Considering the third question

The duration of the impact of the bat is $t _1 = 0.7 \ ms = 0.7 *10^{-3} \ s$

Generally the average force exerted by the bat is mathematically represented as

$F = \frac{I_1}{t_1}$

=> $F = \frac{14.21 }{0.7 *10^{-3}}$

=> $F = 20300 \ N$

7 0

3 years ago