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Stells [14]
3 years ago
11

Which gas law describes the relationship between volume and pressure at a constant temperature?

Chemistry
2 answers:
Iteru [2.4K]3 years ago
6 0

Boyles law is the answer.

-Steel jelly

makvit [3.9K]3 years ago
6 0

Answer : The correct option is, Boyle’s law  

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

Charles' Law : It is defined as the volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T

Avogadro's Law : It is defined as the volume of the gas is directly proportional to the number of moles of the gas at constant pressure and temperature.

V\propto n

Combined gas law : It is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{PV}{T}=K

or,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

From the above information we conclude that the relationship between volume and pressure at a constant temperature is known as Boyle’s law.

Hence, the correct option is, Boyle’s law  

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20 ml of a mixture of C2H6 and C3H8 gases in X : Y mole ratio, is burnt completely by which 52 ml CO2 gas is evolved. If 20 ml o
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The volume of CO2 prodiced when 12 mL of CH4 and 8 mL of C4H10 is burnt is 56 mL.

<h3>What is the equation of the reaction?</h3>

The equation of the combustion of C2H6, CH4, C4H10, and C3H8 gases are given below:

2 C2H6 + 7 O2 ---> 4 CO2 + 6 H20

C3H8 + 5 O2 ---> 3 CO2 + 4 H20

CH4 + 2 O2 ----> CO2 + 2 H2O

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X moles of C2H6 will produce 2X moles of CO2

Y moles of C3H8 will produce 3Y moles of CO2

Thus;

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2X + 3Y = 52 mL ---(2)

Solving for X by substituting in (2)

2 (20 - Y) + 3Y = 52

40 - 2Y + 3Y = 52

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Then X = 8 mL

Volume of CO2 produced when 12 mL of CH4 and 8 mL of C4H10 is burnt = (12 × 2 + 8 × 4) = 56 mL

Therefore, the volume of CO2 produced is 56 mL.

Learn more about moles of gas and volume at: brainly.com/question/23883946

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