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3 years ago

What is the wavelength if the frequency is 29.2 hz?

Chemistry

1 answer:

ZanzabumX [31]3 years ago

8 0

Answer : The wavelength is $1.027\times 10^7m$

Solution : Given,

frequency = 29.2 Hz

Formula used :

$\nu=\frac{c}{\lambda}\\\lambda=\frac{c}{\nu}$

where,

$\nu$ = frequency

$\lambda$ = wavelength

c = speed of light = $3\times 10^8m/s$

Now put all the given values in this formula, we get the wavelength.

$\lambda=\frac{3\times 10^8m/s}{29.2Hz}=0.1027\times 10^8m=1.027\times 10^7m$ $(1Hz=1s^{-1})$

Therefore, the wavelength is $1.027\times 10^7m$

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How many moles of carbon (C) atoms are equivalent to 38.1 g C?

Alla [95]

To convert grams to moles, we need the molar mass of carbon. this can be founded in the periodic table.

molar mass of C= 12.0 g/mol

38.1 g C (1 mol C/ 12.0 grams)= 3.18 moles of C

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3 years ago

How do scientist classify newly discovered organisms into domains and kingdoms? (6th Grade)

olga55 [171]

Answer: Scientists look for cell types, the ability to make food, number of cells in their bodies.

Explanation: Scientists look for cell types, the ability to make food, number of cells in their bodies when placing newly-discovered organisms.

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3 years ago

What lens could get dirty with oil if you move the revolving nosepiece in the wrong direction after viewing under oil immersion?

xxMikexx [17]

From what we know, we can confirm that doing this may dirty and cause harm to your 40x lens.

<h3 /><h3>Why would this cause harm to your lens?</h3>

Oil immersion is a technique that can be quite handy when attempting to view hard-to-see specimens. However, This should be done only with lenses that are made specifically for this, so revolving the nosepiece in the wrong direction will expose the 40x lens to the oil, for which it is not designed, and may cause harm to the equipment.

Therefore, we can confirm that the 40x lens could get dirty with oil if you move the revolving nosepiece in the wrong direction after viewing it under oil immersion.

To learn more about microscopes visit:

brainly.com/question/507443?referrer=searchResults

3 0

2 years ago

Using the information in the table, calculate the number of moles in a \pu{7.89 kg}7.89 kg7, point, 89, space, k, g sample of as

Karolina [17]

We have to find the number of moles in a 7.89 kg sample of aspirin.

The formula of aspirin is: C₉H₈O₄

We are given the molar mass of C, H and O:

H: 1.008 g/mol C: 12.01 g/mol O: 16.00 g/mol

Since one molecule of aspirin has 9 atoms of C, 8 atoms of H and 4 atoms of O, and using the molar masses given, we can calculate the molar mass of aspirin:

molar mass of aspirin = 9 * 12.01 g/mol + 8 * 1.008 g/mol + 4 * 16.00 g/mol

molar mass of aspirin = 180.154 g/mol

Before we find the number of moles we can convert 7.89 kg to g. Since we know that there are 1000 g in 1 kg, we can convert it like this:

1000 g = 1 kg

mass of sample = 7.89 kg * 1000 g/1 kg

mass of sample = 7890 g

Finally, we can find the number of moles in the sample using the molar mass.

number of moles = 7890 g * 1 mol/180.154 g

number of moles = 43.795 moles

Answer: The number of moles in the sample is 43.8 moles (using 3 SF)

7 0

1 year ago

In 1909 Fritz Haber discovered the workable conditions under which nitrogen, N2(g), and hydrogen, H2(g), would combine using to

labwork [276]

Answer : 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.

Solution : Given,

Mass of $NH_3$ = 100 g

Molar mass of $NH_3$ = 27 g/mole

Molar mass of $N_2$ = 28 g/mole

First we have to calculate moles of $NH_3$ .

$\text{ Moles of }NH_3=\frac{\text{ Mass of }NH_3}{\text{ Molar mass of }NH_3}= \frac{100g}{27g/mole}=3.7moles$

The given balanced chemical reaction is,

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

From the given reaction, we conclude that

2 moles of $NH_3$ produced from 1 mole of $N_2$

3.7 moles of $NH_3$ produced from $\frac{1mole}{2mole}\times 3.7mole=1.85moles$ of $N_2$

Now we have to calculate the mass of $N_2$ .

Mass of $N_2$ = Moles of $N_2$ × Molar mass of $N_2$

Mass of $N_2$ = 1.85 mole × 28 g/mole = 51.8 g

Therefore, 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.

5 0

3 years ago