Answer:
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- <u><em>Because the x-intercet of the graph represents volume zero, which indicates the minimum possible temperature or absolute zero.</em></u>
Explanation:
Charle's Law for ideal gases states that, at constant pressure, the <em>temperature</em> and the <em>volume</em> of a sample of gas are protortional.
That means that the graph of the relationship between Temperature, in Kelivn, and Volume is a line, which passes through the origin.
When you work with Temperature in Celsius, and the temperature is placed on the x-axis, the line is shifted to the left 273.15ºC.
Meaning that the Volume at 273.15ºC is zero.
You cannot reach such low temperatures in an experiment, and also, volume zero is not real.
Nevertheless, you can draw the line of best fit and extend it until the x-axis (corresponding to a theoretical volume equal to zero), and read the corresponding temperature.
Subject to the experimental errors, and the fact that the real gases are not ideal, the temperature that you read on the x-axis is the minimum possible temperature (<em>absolute zero</em>) as the minimum possible volume is zero.
<u>Answer:</u> The correct answer is Option b.
<u>Explanation:</u>
To calculate the amount of heat absorbed or released, we use the following equation:
.....(1)
where, q = amount of heat absorbed or released.
m = mass of the substance
c = heat capacity of water = 4.186 J/g ° C
= Change in temperature
We are given:
![m=30g\\\Delta T=[40-0]^oC=40^oC\\q=?J](https://tex.z-dn.net/?f=m%3D30g%5C%5C%5CDelta%20T%3D%5B40-0%5D%5EoC%3D40%5EoC%5C%5Cq%3D%3FJ)
Putting values in equation 1, we get:
q = 5023.2 J
We are given:
![m=40g\\\Delta T=[40-30]^oC=10^oC\\q=?J](https://tex.z-dn.net/?f=m%3D40g%5C%5C%5CDelta%20T%3D%5B40-30%5D%5EoC%3D10%5EoC%5C%5Cq%3D%3FJ)
Putting values in equation 1, we get:
q = 1674.4 J
Heat gained by Trial 1 than trial 2 = 
Hence, the amount of heat gained in Trial 1 about 3347 J more than the heat released in Trial 2.
Thus, the correct answer is Option b.
V(NaOH)=15 mL =0.015 L
C(NaOH)=0.1 mol/L
C(H₂SO₄)=0.05 mol/L
2NaOH + H₂SO₄ = Na₂SO₄ + 2H₂O
n(NaOH)=V(NaOH)C(NaOH)=2n(H₂SO₄)
n(H₂SO₄)=V(H₂SO₄)C(H₂SO₄)
V(NaOH)C(NaOH)=2V(H₂SO₄)C(H₂SO₄)
V(H₂SO₄)=V(NaOH)C(NaOH)/{2C(H₂SO₄)}
V(H₂SO₄)=0.015*0.1/{2*0.05}=0.015 L = 15 mL
Answer:
The halogens, nitrogen and sulphur are covalently bonded to the organic compounds. In order to detect them, the elements need to be converted into their ionic forms. This is done by fusing the organic compound with sodium metal. ... The extract is called sodium fusion extract or Lassaigne's extract.
Though she hits the drum, the papers on the drum also vibrate.
This is due to the fact that when she hits the drum, the shock waves created by the hitting travel through the skin of the drum and radiate outwards. When they encounter the papers, some of this energy is transmitted to the papers and the papers also vibrate.
