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1 year ago

Use the periodic table to choose the element that matches each description.

Chemistry

1 answer:

nika2105 [10]1 year ago

8 0

Using the periodic table to choose the element that matches each description include the following below:

Halogen: iodine

Group IIA: magnesium

Nonreactive: argon

Alkali metal: potassium.

<h3>What is a Periodic table?</h3>

This contains elements which are arranged according to the order of their atomic number in a tabular form. There are 18 groups which are the vertical columns present while there are 8 periods which are the horizontal rows present in the periodic table.

Example of an alkali metal is potassium while the non reactive ones include argon, neon etc. Examples of halogens include chlorine, iodine etc. are the ones which have seven electrons in their outer electron shells thereby just requiring one electron to achieve to obtain a stable octet configuration.

These are therefore the elements which match the descriptions provided in this case and is the most appropriate choice.

Read more about Periodic table here brainly.com/question/15987580

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2 Carbon (C) is found on the Periodic Table; however, Carbon Dioxide (CO2) is not. Why is this the case? А B с D

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Answer:

2 Carbon (C) is found on the Periodic Table; however, Carbon Dioxide (CO2) is not. Why is this the case? А B с D

A Only substances that cannot be broken down into simpler substances are found on the Periodic Table.

B Only gases are found on the Periodic Table.

C Only compounds are found on the Periodic Table.

D Compounds cannot be broken down into simpler substances.

Answer:

Explanation:

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2 years ago

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3 years ago

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2 years ago

A 32.8 g sample of gas occupies 22.414 L at STP. What is the molecular weight of this gas?

olasank [31]

Answer:

32.8g/mole

Explanation:

Given parameters:

Mass of sample of gas = 32.8g

Volume = 22.4L

Unknown:

Molecular weight = ?

Solution:

To solve this problem we must understand that at rtp;

1 mole of gas occupies a volume of 22.4L

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2 years ago

What mass of lithium phosphate would you mass to make 2.5 liter of 1.06 M lithium

alex41 [277]

Answer:

Approximately $3.06 \times 10^{2}\; \rm g$ (approximately $306\; \rm g$ .)

Explanation:

Calculate the quantity $n$ of lithium phosphate in $V = 2.5\; \rm L$ of this $c = 1.06\; \rm M = 1.06\; \rm mol \cdot L^{-1}$ lithium phosphate solution.

$\begin{aligned}n &= c \cdot V\\ &= 2.5\; \rm L \times 1.06\; mol \cdot L^{-1}\\ &= 2.65\; \rm mol\end{aligned}$ .

Empirical formula of lithium phosphate: $\rm Li_3PO_4$ .

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$\rm Li$ : $6.94$ .
$\rm P$ : $30.974$ .
$\rm O$ : $15.999$ .

Calculate the formula mass of $\rm Li_3PO_4$ :

$M(\rm Li_3PO_4) = 3 \times 6.94 + 30.974 + 4 \times 15.999 = 115.79\; \rm g \cdot mol^{-1}$ .

Calculate the mass of that $n = 2.65\; \rm mol$ of $\rm Li_3PO_4$ formula units:

$\begin{aligned}m &= n \cdot M \\ &= 2.65\; \rm mol \times 115.79\; \rm g\cdot mol^{-1} \\ &\approx 3.06 \times 10^{2}\; \rm g \end{aligned}$ .

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2 years ago