Answer:
32 K is approx. -241.15° C
Answer:Ian is looking at cells using a microscope. He sees a nucleus and a large vacuole in the central area of a cell. What type of cell is he most likely looking at?
Explanation:
Ian is looking at cells using a microscope. He sees a nucleus and a large vacuole in the central area of a cell. What type of cell is he most likely looking at?
Answer:
for the reaction is -3.059 kJ/mol.
Explanation:
Reaction equilibrium: ![N_{2}O_{4}(g)\rightleftharpoons 2NO_{2}(g)](https://tex.z-dn.net/?f=N_%7B2%7DO_%7B4%7D%28g%29%5Crightleftharpoons%202NO_%7B2%7D%28g%29)
Reaction quotient (Q) for this reaction at
and
is:
= ![\frac{(0.122)^{2}}{0.453}](https://tex.z-dn.net/?f=%5Cfrac%7B%280.122%29%5E%7B2%7D%7D%7B0.453%7D)
= 0.0329
We know,
, where
is standard free energy change, R is gas constant and T is temperature in kelvin scale.
Here,
= 5.40 kJ/mol
So, ![\Delta G=(5.40\times 10^{3}J/mol)+[8.314J.mol^{-1}.K^{-1}\times 298K\times ln(0.0329)]](https://tex.z-dn.net/?f=%5CDelta%20G%3D%285.40%5Ctimes%2010%5E%7B3%7DJ%2Fmol%29%2B%5B8.314J.mol%5E%7B-1%7D.K%5E%7B-1%7D%5Ctimes%20298K%5Ctimes%20ln%280.0329%29%5D)
= -3059 J/mol
= -3.059 kJ/mol
Answer:
19.9 atoms
Explanation:
Grams --- Moles --- Atoms
You're converting from atoms (molecules) to moles.
You do not have to calculate the mass of "di phosphorus pentoxide."
Since you're already given 1.2x10^25 atoms, you start with that. You need to cancel out the atoms, so you need Avogadro's number as shown in the image.
(This has nothing to do with the problem) But in case if you're wondering, the "di" in phosphorus means there's 2 phosphorus and the "pent" means that there are 5 oxygens. So P2O5. Go to your periodic table, multiply their respective atomic masses. You would multiply phosphorus twice and oxygen 5 times. And add them up to get the overall mass.
I hope this helped!
Answer:
Cis and trans isomers
Explanation:
Existence of double bond in carbon rich compound confirms the presence of geometrical isomer in the compound. The compound showing geometrical isomer exists as cis and trans isomers.
Substituents or functional group around double bond decides that the compound will be cis or trans.
If functional group or bigger substituents are present on the same side of the double bond, the compound will be cis.
If functional group or bigger substituents are present on the opposite of the double bond, the compound will be trans.