I belive its 4.76 because it would not be 0.55
<h3>
Answer:</h3>
1.07 M
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Molarity = moles of solute / liters of solution
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Given] 2.14 moles (CH₃)₂SO
[Given] 2.00 L
[Solve] Molarity
<u>Step 2: Solve</u>
- Substitute in variables [Molarity]: x M = 2.14 moles (CH₃)₂SO / 2.00 L solution
- [Molarity] Divide: x = 1.07 M
Answer:
I believe it is a hope this helps
Oxidation
iron+oxygen happened
Given :
Number of moles , n = 36.25 mol .
Molarity , M = 1.25 M .
To Find :
The volume of water required .
Solution :
Moarity is given by :

So , 
Here , n is number of moles and M is molarity .
Putting all values in above equation , we get :

Therefore , volume of water required is 29 L .