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Anastasy [175]
3 years ago
6

Which of the following can explain the daily change in sea level observed along a coast?

Chemistry
1 answer:
salantis [7]3 years ago
5 0
The answer for the question above is A. the gravitational pull of the moon on the water near the coast. The sun and and the moon are responsible for the rising and falling of the ocean tides. The gravitational pull of the moon and the sun makes the water in the oceans bulge, causing a continuous change between high and low tide. 
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What type of bond is present between two atoms of tungsten in a light bulb filament?
stiks02 [169]

Answer:

ionic bonding

Explanation:

hope it helps

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2 years ago
Valence electrons are important because these are the only electrons involved with an atom's
Salsk061 [2.6K]
<span>Valence electrons are important because these are the only electrons involved with an atom's chemical reactivity.</span>
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3 years ago
56789x09876<br><br><br><br><br><br><br> Does anyone want to rp?? Any kind of rp I'm just bored
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7 0
3 years ago
Sulfuric acid (H2SO4) has a molar mass of 98.1 g/mol. How many oxygen atoms are found in 75.0 g of H2SO4?
nekit [7.7K]

Answer:

18.33 ×10²³ atoms

Explanation:

Given data:

Molar mass of sulfuric acid = 98.1 g/mol

Mass of sulfuric acid = 75.0 g

Number of of oxygen atom present = ?

Solution:

Number of moles of sulfuric acid:

Number of moles = mass/molar mass

Number of moles = 75.0 g/ 98.1 g/mol

Number of moles =0.761 mol

one mole of  sulfuric acid  contain four mole of oxygen atom.

0.761 mol × 4 = 3.044 mol

1 mole = 6.022×10²³ atoms of oxygen

3.044 mol ×  6.022×10²³ atoms of oxygen / 1mol

18.33 ×10²³ atoms

3 0
3 years ago
weather balloon is filled with helium to a volume of 340 L at 30 ∘C and 751 mmHg . The balloon ascends to an altitude where the
valentinak56 [21]

Answer: Thus the volume of the balloon at this altitude is 419 L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 751 mm Hg

P_2 = final pressure of gas = 495 mm Hg

V_1 = initial volume of gas = 340 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 30^oC=273+30=303K

T_2 = final temperature of gas = -27^oC=273-27=246K

Now put all the given values in the above equation, we get:

\frac{751\times 340}{303}=\frac{495\times V_2}{246}

V_2=419L

Thus the volume of the balloon at this altitude is 419 L

8 0
3 years ago
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