The amount of the magnesium in the sample in ppm is 497 ppm.
<h3>What is parts per million?</h3>
The term parts per million refers to one of the manners in which concentration is expressed. It is common in oceanography and analytical chemistry.
Given that;
Mass of Mg= 0.0549 g
Mass of the sample = 110.52 g
Amount in PPM = 0.0549 g/110.52 g * 10^6
= 497 ppm
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First let us compute for the number of moles of butane
(molar mass = 58.12 g/mol)
number of moles = 145 g / (58.12 g/mol) = 2.49 mol
<span>We use the ideal
gas equation to calculate the volume:</span>
<span> V = n R T / P</span>
V = 2.49 mol * 62.36367 L torr / mol K * 308.15 K / 745
torr
<span>V = 64.35 L</span>
Answer:
To avoid variation due to concentration
Explanation:
Hope this helps :)
<span>What mass of water must be used to dissolve 500g C2H5OH to prepare a 3.00 m solution?
</span>500g C2H5OH ( 1 mol / 46.07 g ) / 3 mol/kg water = 3.62 kg water needed<span>
What is the molality of a solution that contains 80.0 g Al2(SO4)3 in 625 g H2O?
Molality = 80.0 g </span>Al2(SO4)3 (1 mol / 342.15 g) / .625 kg H2O = 0.374 m<span>
25 g of NaOH is dissolved in 120 g of water. What is the molality?
Molality = 25 g NaOH ( 1 mol / 40 g ) / .120 kg = 5.21 m</span>