Answer:
tan²x + 1 = sec²x is identity
Step-by-step explanation:
* Lets explain how to find this identity
∵ sin²x + cos²x = 1 ⇒ identity
- Divide both sides by cos²x
∵ sin x ÷ cos x = tan x
∴ sin²x ÷ cos²x = tan²x
- Lets find the second term
∵ cos²x ÷ cos²x = 1
- Remember that the inverse of cos x is sec x
∵ sec x = 1/cos x
∴ sec²x = 1/cos²x
- Lets write the equation
∴ tan²x + 1 = 1/cos²x
∵ 1/cos²x = sec²x
∴ than²x + 1 = sec²x
- So we use the first identity sin²x + cos²x = 1 to prove that
tan²x + 1 = sec²x
∴ tan²x + 1 = sec²x is identity
My advice is don't smoke and make sure you don't keep the two close together. Hope this helped,
The answer is going to be 3,495
Answer:
2nd option
Step-by-step explanation:
You're goal is to isolate b by itself. The only part you need to worry about is the equation, the rest of the word problem is irrelevant.
The whole process of solving this is to do PEMDAS in reverse.
So first add/subtract all the values that does not have a <em>b</em> attach to it to the other side.
then multiply/divide all the values that is not a <em>b</em> to get the b-value by itself
Answer:
anong grade po yan
Step-by-step explanation:
idont know