Question

if you begin with 210.3 g of Cl2, how many grams of HCl will you end up with? CH4 + 3Cl2 → CHCl3 + 3HCl *

Answer 1

Answer:

108.04g

Explanation:

Looking at the balanced chemical equation theoretically, we can see that 3 moles of chlorine yielded 3 moles of HCl. This means that they have equal mole ratio.

Now let’s get the actual reactive moles. The number of moles is obtained by dividing the mass by the molar mass.

The molecular mass of chlorine gas is (2 * 35.5) = 72g/mol

The number of moles is thus 210.3/71 = 2.96 moles

Since the number of moles are equal, the number of moles of HCl produced too is 2.96 moles.

Now to get the mass of HCl produced, we multiply the number of moles by the molar mass of HCl. The molar mass of HCl is 36.5g/mol

The mass is thus 2.96 * 36.5 = 108.04g