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irinina [24]
2 years ago
15

Ethanol is a/an A. organic acid. B. substituted hydrocarbon. C. aromatic hydrocarbon. D. carbohydrate.

Chemistry
1 answer:
Rudik [331]2 years ago
8 0
Ethanol is a substituted hydrocarbon. The "ol" suffix used in ethanol is for the functional group -OH, or alochol group. When any functional group is attached to a pure hydrocarbon, that hydrocarbon shows properties of that functional group. 
For ethane as well, which have molecular formula of C2H6, when one hydrogen is substituted by one -OH group it becomes C2H5OH which we call as ethanol or ethyl alcohol. If two hydrogen are substituted, it becomes -diol and as such.
There are number of ways to prepare ethanol by pure hydrocarbon. Generally ethanol can be prepared by fermentation of starch and molasses. Also various organic reaction gives ethanol as product. When ethene is  reacted with steam catalysed by phosphoric acid.
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Which of the following statements is true regarding both theories and laws?
Mariana [72]

Answer:

D. Supported by observations

Explanation:

Because theories change over time, they both need to be proven, they do not go off of consensus, but they do need to be supported by observations.

HOPE IT HELPS❣️

6 0
2 years ago
Where did they start water conservation in tamil nadu . short answer
OleMash [197]

Explanation:

The 2019 water crisis in Chennai has made us realize the importance of saving water more than ever. Water, as we all know, is a finite resource without which our planet would be a barren wasteland. Today with our increasing population it would be logical to say that our water consumption has also increased. And with increasing demand and lesser supply, water scarcity arises. Our ancestors who had foreseen the potential dangers of water scarcity had developed methods to conserve water that was suited for the varied terrain of the Tamil-speaking kingdoms.

Traditional Rainwater Conservation methods of Tamil Nadu

Eri

There are no perennial rivers in Tamil Nadu except the Thamirabharani River which flows through Thirunelveli district. And so, several hundred years ago a simple system was devised to utilize the rainwater to the fullest. An Eri or tank system is one of the oldest forms of water conservation systems in India. Many Eris are still in use in Tamil Nadu and play an active role in irrigation. They act as water reservoirs and flood control systems. They prevent soil erosion, recharge groundwater, and prevent wastage of runoff water during heavy rainfall.

Kudimaramathu

Kudimaramathu is one of the old traditional practice of stakeholders participating in the maintenance and management of irrigation systems. During earlier days, citizens of a village used to actively participate in maintaining the water bodies of their village by deepening and widening the lakes and ponds and restoring the water bodies back to their original form. The silt, rich in nutrients, collected in the process would be used by the farmers themselves in their field. A sense of collective ownership ensured the continued survival of the water bodies.

6 0
2 years ago
A gas system contains 2.00 moles of O2 and CO2 gas, has an initial temperature of 25.0 oC and is under 1.00 atm of pressure. If
Ainat [17]

Answer:

V_2=52.2L

Explanation:

Hello there!

In this case, by bearing to to mind the given conditions, it is firstly possible to determine the initial volume of the closed system via the ideal gas equation:

PV=nRT\\\\V=\frac{2.00mol*0.08206\frac{atm*L}{mol*K}*298.15K}{1.00 atm} \\\\V=48.9L

Which is V1 in the Charles' law:

\frac{T_2}{V_2} =\frac{T_1}{V_1}

And of course, T1 is 298.15 (25+273.15). Therefore, by solving for V2 as the final volume, we obtain:

V_2=\frac{V_1T_2}{T_1}\\\\V_2=\frac{48.9L*(45+273.15)K}{(25+273.15)K}  \\\\V_2=52.2L

Best regards!

8 0
3 years ago
Using the following reaction:
Romashka-Z-Leto [24]

Answer:

Mn is the oxidizing agent.

N is the reducing agent.

Explanation:

Hello!

In this case, according to the undergoing chemical reaction, it is seen that the manganese in KMnO4 has an oxidation state of 7+, in MnSO4 of 2+ and nitrogen in KNO2 is 3+ and in KNO3 is 5+; thus we have the following half-reactions:

Mn^{7+}+5e^-\rightarrow Mn^{2+}\\\\N^{3+}\rightarrow N^{5+}+2e^-

Thus, since manganese is undergoing a decrease in the oxidation state, we infer it is the oxidizing agent whereas nitrogen, undergoing an increase in the oxidation state is the reducing agent.

Best regards!

5 0
2 years ago
During a laboratory experiment, 36.12 grams of Aboz was formed when O2 reacted with aluminum metal at 280.0 K and 1.4 atm. What
kvv77 [185]

Answer:

8.70 liters

Explanation:

  • 3O₂+ 4Al → 2AI₂O₃

First we <u>convert 36.12 g of AI₂O₃ into moles</u>, using its <em>molar mass</em>:

  • 36.12 g ÷ 101.96 g/mol = 0.354 mol AI₂O₃

Then we <u>convert AI₂O₃ moles into O₂ moles</u>, using the stoichiometric coefficients of the reaction:

  • 0.354 mol AI₂O₃ * \frac{3molO_2}{2molAl_2O_3} = 0.531 mol O₂

We can now use the <em>PV=nRT equation</em> to <u>calculate the volume</u>, V:

  • 1.4 atm * V = 0.531 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 280.0 K
  • V = 8.708 L
5 0
3 years ago
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