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irinina [24]
3 years ago
15

Ethanol is a/an A. organic acid. B. substituted hydrocarbon. C. aromatic hydrocarbon. D. carbohydrate.

Chemistry
1 answer:
Rudik [331]3 years ago
8 0
Ethanol is a substituted hydrocarbon. The "ol" suffix used in ethanol is for the functional group -OH, or alochol group. When any functional group is attached to a pure hydrocarbon, that hydrocarbon shows properties of that functional group. 
For ethane as well, which have molecular formula of C2H6, when one hydrogen is substituted by one -OH group it becomes C2H5OH which we call as ethanol or ethyl alcohol. If two hydrogen are substituted, it becomes -diol and as such.
There are number of ways to prepare ethanol by pure hydrocarbon. Generally ethanol can be prepared by fermentation of starch and molasses. Also various organic reaction gives ethanol as product. When ethene is  reacted with steam catalysed by phosphoric acid.
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Collision of which two types of plates create the deepest earthquakes? Why do you think this is?
Elis [28]

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7 0
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2. A sample of neon gas has a volume of 87.6 L at STP. How many moles are present?
PSYCHO15rus [73]

Answer:

                      3.91 moles of Neon

Explanation:

According to Avogadro's Law, same volume of any gas at standard temperature (273.15 K or O °C) and pressure (1 atm) will occupy same volume. And one mole of any Ideal gas occupies 22.4 dm³ (1 dm³ = 1 L).

Data Given:

                 n = moles = <u>???</u>

                 V = Volume = 87.6 L

Solution:

               As 22.4 L volume is occupied by one mole of gas then the 16.8 L of this gas will contain....

                          = ( 1 mole × 87.6 L) ÷ 22.4 L

                          = 3.91 moles

<h3>2nd Method:</h3>

                     Assuming that the gas is acting ideally, hence, applying ideal gas equation.

                              P V  =  n R T      ∴  R  =  0.08205 L⋅atm⋅K⁻¹⋅mol⁻¹

Solving for n,

                              n  =  P V / R T

Putting values,

                              n  =  (1 atm × 87.6 L)/(0.08205 L⋅atm⋅K⁻¹⋅mol⁻¹ × 273.15K)

                              n  =  3.91 moles

Result:

          87.6 L of Neon gas will contain 3.91 moles at standard temperature and pressure.

7 0
3 years ago
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