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irinina [24]
3 years ago
15

Ethanol is a/an A. organic acid. B. substituted hydrocarbon. C. aromatic hydrocarbon. D. carbohydrate.

Chemistry
1 answer:
Rudik [331]3 years ago
8 0
Ethanol is a substituted hydrocarbon. The "ol" suffix used in ethanol is for the functional group -OH, or alochol group. When any functional group is attached to a pure hydrocarbon, that hydrocarbon shows properties of that functional group. 
For ethane as well, which have molecular formula of C2H6, when one hydrogen is substituted by one -OH group it becomes C2H5OH which we call as ethanol or ethyl alcohol. If two hydrogen are substituted, it becomes -diol and as such.
There are number of ways to prepare ethanol by pure hydrocarbon. Generally ethanol can be prepared by fermentation of starch and molasses. Also various organic reaction gives ethanol as product. When ethene is  reacted with steam catalysed by phosphoric acid.
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Which lists the steps of mitosis in the correct order?
Sindrei [870]

Answer: The last one

Explanation: because Im in the 8th grade and I did this in the 6th

GIVE BRAINLEIST LIKE U PROMISED

4 0
3 years ago
Can anyone help with properties of non-metals?
Katen [24]
Dull (not shiny)
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3 0
3 years ago
If a tree dies and the trunk remains undisturbed for 13,750 years, what percentage of the original 14c is still present? (the ha
defon

Answer:

18.94%.

Explanation:

  • The decay of carbon-14 is a first order reaction.
  • The rate constant of the reaction (k) in a first order reaction = ln (2)/half-life = 0.693/(5730 year) = 1.21 x 10⁻⁴ year⁻¹.
  • The integration law of a first order reaction is:

<em>kt = ln [A₀]/[A]</em>

k is the rate constant = 1.21 x 10⁻⁴ year⁻¹.

t is the time = 13,750 years.

[A₀] is the initial percentage of carbon-14 = 100.0 %.

[A] is the remaining percentage of carbon-14 = ??? %.

∵ kt = ln [Ao]/[A]

∴ (1.21 x 10⁻⁴ year⁻¹)(13,750 years) = ln (100.0%)/[A]

1.664 =  ln (100.0%)/[A]

Taking exponential for both sides:

5.279 = (100.0%)/[A]

<em>∴ [A]</em> = (100.0%)/5.279 = <em>18.94%.</em>

8 0
3 years ago
A gas balloon has a volume of 80.0 mL at 300K, and a pressure of 50.0 kPa. If the pressure changes to 80 kPa and the temperature
fomenos

Answer:  The new volume is 53.3 ml

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas =  50.0 kPa

P_2 = final pressure of gas = 80.0 kPa

V_1 = initial volume of gas = 80.0 ml

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 300K

T_2 = final temperature of gas = 320K

Now put all the given values in the above equation, we get:

\frac{50.0\times 80.0}{300}=\frac{80.0\times V_2}{320}

V_2=53.3ml

The new volume is 53.3 ml

4 0
3 years ago
How can phisical change what a subtance?
solmaris [256]
Physical change can change a substance by affecting the form of a chemical change.
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Molded (Bread)
Boiled (Water)
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3 0
3 years ago
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