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AlekseyPX
3 years ago
11

Plz help!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
e-lub [12.9K]3 years ago
4 0
The original triangle had side lengths of 12. The perimeter was 36

Then if you divide each side by 4, each side would be 3 and the new triangle's perimeter would be 9. The difference of them would be 36-9 which is 27. The answer is 27. Hope that helped
antoniya [11.8K]3 years ago
4 0
The answer is 27 I did my math in a calculator, and I told my math teacher I'm home schooled
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2. Eric had $197 in his savings account before he was paid his weekly salary. His current
Nezavi [6.7K]

Answer:

197+n = 429

Step-by-step explanation:

He starts with 197,  he adds his salary, he ends with 429

197+n = 429

5 0
3 years ago
Read 2 more answers
There are 180 girls in a mixed school. lf the ratio of girls is to boys is 4:3 , the total number of students in the school is w
Angelina_Jolie [31]

Answer:

315

Step-by-step explanation:

No. of girls be g

No. of boys be b

g= 180

g/b = 4/3

b = 3g/4

b= 3(180/4)

b= 3*45

b= 135

.

Find b+g

= 135 + 180

= 315

3 0
3 years ago
Angles: can somebody tell me the angles of X, Y, Z please p.s 25 points if answered correctly
antoniya [11.8K]

Answer:

X=30; Z=80; Y=70

Step-by-step explanation:

The straight lines equal 180 and you subtract 180 to 150 and 180 to 100 to get 30 and 80 and the inside of a triangle is 180 and you subtract 30 and 80 to 180 to get 70.

3 0
3 years ago
Anyone know how to find the constant of proportionality???!!!
dmitriy555 [2]

Answer:

You find the constant of proportionality by how much u need to add or subtract the same number to get the same answer and in a graph you need to see if the line goes through the origin (0,0).

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Consider a population consisting of the number of teachers per college at small 2-year colleges. Suppose that the number of teac
agasfer [191]

Answer:

a) \frac{8}{9} =0.89

b) 0.8413

Step-by-step explanation:

we know that

P(║ x -\mu║ \leq  k\sigma) \geq 1 -\frac{1}{k^2}

so, \mu = 150, \sigma = 20

k =  \frac{210 - 150}{20} =\frac{150 - 90}{20} = 3

P(║ x -150 ║ \leq  3\times 20) \geq 1 -\frac{1}{3^2} = \frac{8}{9}

x - N(150, 20^2)

P(X \leq 170) = 0.8413447

check

P norm = \frac{170 - 150}{20}= 0.8413447

8 0
3 years ago
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