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Kay [80]
4 years ago
11

You are driving 12 meters per second. What is your speed in miles per hour? (1.6km=1 mike) EXPLAIN

Physics
1 answer:
Blizzard [7]4 years ago
8 0

1.6km = 1 mike? Wow that guy is tall.

I think you meant 1.6 km = 1 mile? Okay then if we're going 12 meters per second how much would you travel in one hour? First we need to figure out how many seconds are in an hour.  There are 60 seconds in a minute and 60 minutes in an hour so:

60×60=3600 seconds in an hour

Now we will multiply that by 12 meters per second and we get:

12\frac{m}{s} \times 3600 s=43200m

And 43200 meters is 43.2 km (1000 meters in 1 kilometer) meaning 43.2 kilometers an hour.  Since there are 1.6 km in one mile we must divide 43.2km to 1.6.

\frac{43.2}{1.6}=27mph

And so your speed is 27 miles per hour.

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3 years ago
A 111 kg 111 kg horizontal platform is a uniform disk of radius 1.67 m 1.67 m and can rotate about the vertical axis through its
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Answer:

287.19 kg.m²

Explanation:

Given that :

The mass M of the horizontal platform  = 111 kg

The radius R of the uniform disk = 1.67 m

mass  of the person standing m_p = 64.7 kg

distance of the person standing d_p = 1.15 m

mass of the dog m_d = 25.7 kg

distance of the dog d_d = 1.35 m

Considering the moment of inertia of the object in the system; the net moment of the inertia can be expressed as:

=  \frac{MR^2}{2}+m_pd_p^2+m_dd_d^2

= (\frac{111*1.67^2}{2})+ (64.7 *1.15^2)+ (25.7*1.35^2)

= 287.19 kg.m²

5 0
4 years ago
Which of the following statements is an example of climate?
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8 0
3 years ago
Two forces act concurrently on an object. Their
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4 0
3 years ago
What is the binding energy of an electron that requires a photon with a maximum wavelength of 430 nm to eject it? If a photon wi
romanna [79]

Answer:

The kinetic energy of the electron is 4.98\times 10^{-18}\ J.

Explanation:

Given that,

The maximum wavelength of a photon is 430 nm.

The frequency of a photon is 8.21\times 10^{15}\ Hz

It is a case of photoelectric effect. The relation between the kinetic energy and the the work function as :

K=hf-W_o\\\\K=hf-h\dfrac{c}{\lambda}\\\\K=h(f-\dfrac{c}{\lambda})\\\\K=6.63\times 10^{-34}\times (8.21\times 10^{15}-\dfrac{3\times 10^8}{430\times 10^{-9}})\\\\K=4.98\times 10^{-18}\ J

So, the kinetic energy of the electron is 4.98\times 10^{-18}\ J.

8 0
3 years ago
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