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4 years ago

________ capture solar energy and use photosynthesis to produce sugars.

Physics

1 answer:

vovikov84 [41]4 years ago

8 0

Answer:

Option (A)

Explanation:

The green plants are capable of synthesizing their own food, in the presence of sunlight, CO₂ and water, and in return, liberates food and oxygen (O₂). This process is known as photosynthesis. This process is possible due to the presence of chlorophyll pigments on the plant leaves.

These green plants are also known as producers, because they are able to generate food for the consumers.

Thus, the correct answer is option (A).

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Which form of energy moves spontaneously from hot objects to cold objects?

Mumz [18]

Answer:

heat

Explanation:

google ( ╹▽╹ )✧◝(⁰▿⁰)◜✧

6 0

3 years ago

You want to see how your new belt buckle matches your new hat. Your eyes are 114 mm below the top of the hat and 800 mm above th

damaskus [11]

Answer:

$x=0.057m$

$h=0.457m$

Explanation:

From the question we are told that

Distance of eyes from the top of hat $d_1=114mm$

Distance of eyes from buckle $d_2=800mm$

Generally position of mirror relative eyes x is mathematically given as

$x=\frac{114}{2}$

$x=57mm$

$x=0.057m$

Generally the height of the mirror h is mathematically given as

$h=\frac{(Buckle\ below\ the\ hat)+(Buckle\ below\ the\ hat)}{2}$

$h=\frac{(114)+(800)}{2}$

$h=457mm$

$h=0.457m$

7 0

3 years ago

An electron is projected with an initial speed v0 = 1.10 x 10⁶ m/s into the uniform field between the parallel plates. The dista

ArbitrLikvidat [17]

Answer:

a) $E=364N/C$

b) No

Explanation:

A) Because the electron is affected by an acceleration force in this case by the electric field, we can use the formulas of 2-dimension movement.

We will assume the electron missed the upper plate, so we need to calculate the time to travel all the way through the plate, that is:

$x=v_x*t$

$where:\\x=distance\\v=speed\\t=time$

so:

$t=\frac{x}{v_x}=\frac{0.02m}{1.6\cdot 10^6m/s}\\\\t=1.25\cdot10^{-8}$

the electron experiences an accelerated motion in the vertical direction, so we can obtain the acceleration of the electron:

$y=\frac{1}{2}.a.t^2\\\\where:\\y=vertical\_distance\\a=acceleration\\t=time$

so:

$a=\frac{2.y}{t^2}\\\\a=\frac{2*(\frac{0.01}{2}m)}{(1.25\cdot10^{-8}s)^2}\\\\a=6.4\cdot10^{13} m/s^2$

now we can use the relation:

$F=m.a=E.q\\so\\E=\frac{m.a}{q}$

$where:\\\\E=electric\_field\\m=electron\_mass=9.1\cdot10^{-31}kg\\q=Charge=1.6\cdot10^{-19}\\a=acceleration$

Now we can calculate the electric field:

$E=\frac{9.1\cdot10^{-31}kg\cdot6.4\cdot10^{13}m/s^2}{1.6\cdot10^{-19}C}\\\\E=364N/C$

B) Because the proton has the same charge but positive it will go in the opposite direction, so because we assume the electron didn't touch the plate, the proton won't.

5 0

3 years ago

Lana does her homework as soon as she can after class, but she still doesn't undertand everything she suppose to learn. what cou

Lilit [14]

I added a screenshot with the complete question

Answer:
D. Ask her instructor questions about it the next day

Explanation:
We are given that Lana doesn't understand everything she's supposed to learn from the homework.

Let's check the options:
1- start working on it eve earlier
We know that she works on the homework as soon as she can. Working on it even earlier will not help her understand the difficult parts

2- put it off until she's ready to work on it
This is not the best option as it wont help her understand difficult parts. On the contrary, she might lose the time she has to practice the parts she understands and gain as much knowledge as possible

3- Only work on it directly before going to class.
this is the same as option 2. She might not even be able to finish it before the class

4- Ask her instructor questions about it the next day
This is the best solution as it will help her recap what she needs to learn and understand any difficult concepts as soon as possible which will help optimize her benefits

Hope this helps :)

7 0

3 years ago

Read 2 more answers

a model rocket is launched at an angle of 55 to the horizontal with a momentum of 20 kg-m/. If the vertical component of its vel

den301095 [7]

$Given:\\ \alpha =55^\circ\\p=20kg\cdot \frac{m}{s} \\v_v=40 \frac{m}{s} \\\\Find:\\m=?\\\\Solution:\\\\p_v=mv_v\Rightarrow m= \frac{p_v}{v_v} \\\\ \frac{p_v}{p} =\cos \alpha \Rightarrow p_v=p\cos \alpha \\\\m= \frac{p\cos \alpha }{v_v} \\\\m= \frac{20kg\cdot \frac{m}{s} \cdot \cos 55^\circ }{40 \frac{m}{s} } \approx 0.287kg=287g$

4 0

3 years ago