Answer:
i. Subtract v₀² from both of the equation.
ii. Divide both side of the equation by 2
iii. Divide both side of the equation by (x – x₀)
a = (v² – v₀²) / 2(x – x₀)
Explanation:
v² = v₀² + 2a(x – x₀)
To solve for a in the expression above, do the following:
i. Subtract v₀² from both of the equation.
v² – v₀² = v₀² – v₀² + 2a(x – x₀)
v² – v₀² = 2a(x – x₀)
ii. Divide both side of the equation by 2
(v² – v₀²) /2= 2a(x – x₀)/2
(v² – v₀²) /2 = a(x – x₀)
iii. Divide both side of the equation by (x – x₀)
(v² – v₀²) /2 ÷ (x – x₀) = a(x – x₀)/(x – x₀)
(v² – v₀²) /2 × 1/ (x – x₀) = a
a = (v² – v₀²) / 2(x – x₀)
Answer:
A. FITT
Explanation:
F - Frequency - how often she should exercise
I - Intensity - how hard she should work out
T - Time - how long each workout should last
T - Type - how many different exercises/activities she should complete
Answer: 
Explanation:
Given : The escape velocity : 
We know that 1 mile = 1609 meters (approx)
and 1 hour= 3600 seconds
To convert escape velocity 2.5 x 10 miles per hour into m/s , we need to multiply it by 1609.34 and divide it by 3600.
Thus, the escape velocity in m/s is given by :-

Hence, the speed in m/s = 11.17
Answer:


Explanation:
As we know that for perfectly elastic collision total mechanical energy is always conserved
so we will have



now we also know that total moment of the system is conserved in any collision because there is no external force on it
so we will have


