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Black_prince [1.1K]
3 years ago
13

Why might it be important to know your inherited traits passed down by your parents?

Physics
1 answer:
ExtremeBDS [4]3 years ago
3 0

Answer:

health factors that could harm you or your offspring

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A machine puts out 6,000 J of work. To produce that much work the machine
topjm [15]

Answer:

Efficiency of the machine = 75%

Explanation:

Given:

Input work = 8,000 J

Output work = 6,000 J

Find:

Efficiency of the machine

Computation:

Efficiency of the machine = [Output work / Input work]100

Efficiency of the machine = [6,000 / 8,000]100

Efficiency of the machine = 75%

5 0
3 years ago
Define suspension and list two examples.
tigry1 [53]
<span>Suspension, chemistry definition is a heterogenous mixture, meaning one substance is different from another, when mixed, either of the substance (particularly the solid one), do not mix evenly. It could clearly be seen when one mixes a solution in a suspension state because it forms a cloudy solution, Best example of this is mud. In mud, though there is a mixture of solid and liquid, there is still evident traces of solid particles that do not mix evenly in the solution.</span>
3 0
3 years ago
2) What are the directions of the velocity and acceleration of an object in
zaharov [31]
Motion because the motion is the range
7 0
4 years ago
Read 2 more answers
A ray of monochromatic light ( f = 5.09 × 10^14 Hz) passes from air into Lucite at an angle
harina [27]
     Let us consider the air with the index 1 and the lucite with index 2. Using the Snell's Secound Law, we have:

\frac{sen\O_{2}}{sen\O_{1}} = \frac{n_{2}}{n_{1}} \\ sen\O_{2}= \frac{n_{2}*sen\O_{1}}{n_{1}}
 
     Entering the unknowns, remembering that the air refrective index is 1 and the lucite refrective index is 1.5, comes:

sen\O_{2}= \frac{n_{2}*sen\O_{1}}{n_{1}} \\ sen\O_{2}= \frac{1.5* \frac{1}{2} }{1} \\ sen\O_{2}=0.75
  
     Using the arcsin properties, we get:

sen\O_{2}=0.75 \\ arcsin(0.75)=\O_{2} \\ \boxed {\O_{2}=48.59^o}

Obs: Approximate results, and the drawing is attached

If you notice any mistake in my english, let me know, because i am not native.

6 0
3 years ago
On earth, the solar constant is approximately I = 1367 W/m2 . This corresponds to the power per unit area that a detector at the
d1i1m1o1n [39]

Answer:

Explanation:

for earth -sun system

E = σ T⁴ ,  E is radiation emitted by sun at temperature T

E = 4π R₁²  x solar constant on earth , R₁ is distance between earth and sun.

for marsh -sun system

E = σ T⁴ ,  E is radiation emitted by sun at temperature T

E = 4π R₂²  x solar constant on Mars , R₂ is distance between earth and sun.

from two equation ,

4π R₂²  x solar constant on Mars = 4π R₁²  x solar constant on earth

solar constant on Mars = (R₁ / R₂ )² x solar constant on earth

6 0
4 years ago
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