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Ad libitum [116K]
3 years ago
12

Water at 20oC flows through a long elliptical duct 30 cm wide and 22 cm high. What average velocity, in m/s, would cause the wei

ght flow to be 500 lbf/s?
Physics
2 answers:
mars1129 [50]3 years ago
8 0

Explanation:

The given data is as follows.

   Fluid is water so, density \rho = 1000 kg/m^{3}

  Weight flow rate = 500 lbf/s = 2224.11 N/sec

  Cross-sectional area (A) = \pi \times \frac{30}{2} \times \frac{22}{2}

                                         = 0.05184 m^{2}

Hence, weight flow rate will be given as follows.

        w = \rho \times g \times A \times V

    2224.11 N/sec = \rho \times g \times A \times V

        V = \frac{2224.11}{1000 \times 9.81 \times 0.05184} m/s

            = 4.373 m/s

Thus, we can conclude that average velocity in the given case is 4.373 m/s.

gizmo_the_mogwai [7]3 years ago
8 0

Answer:

Explanation:

length of major axis, 2a = 30 cm

a = 15 cm = 0.15 m

length of minor axis, 2b = 22 cm

b = 11 cm = 0.11 m

Weight flow, mg = 500 lbf/s = 2224.1 N/s

Area of duct, A = π ab = 3.14 x 0.15 x 0.11 = 0.0518 m²

Let v be the velocity

Volume per second = mass per second / density

Area x velocity = mass per second / density

0.0518 x v = 2224.1 / (9.8 x 1000)

v = 4.4 m/s

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Answer

t = 367.77 s = 6.13 min

Explanation:

According to the law of conservation of energy:

Heat\ Supplied\ By \ Heater = Heat\ Absorbed\ by\ Glass + Heat\ Absorbed\ by\ Water\\Pt = m_gC_g\Delta T_g + m_wC_w\Delta T_w\\

where,

P = Electric Power of Heater =  300 W

t = time required = ?

m_g = mass of glass = 300 g = 0.3 kg

m_w = mass of water = 250 g = 0.25 kg

C_g = speicific heat of glass = 840 J/kg.°C

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ΔT_g = ΔT_w = Change in Temperature of Glass and water = 100°C - 15°C

ΔT_g = ΔT_w = 85°C

Therefore,

(300\ W)(t) = (0.3\ kg)(840\ J/kg.^oC)(85^oC)+(0.25\ kg)(4184\ J/kg.^oC)(85^oC)\\

<u>t = 367.77 s = 6.13 min</u>

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