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dangina [55]
3 years ago
11

Sixty-five randomly selected car salespersons were asked the number of cars they generally sell in one week. Fourteen people ans

wered that they generally sell three cars; nineteen generally sell four cars; twelve generally sell five cars; nine generally sell six cars; eleven generally sell seven cars.

Mathematics
1 answer:
elena-s [515]3 years ago
6 0

Answer:

The questions are

  1. What does the frequency column in the attached table sum to?
  2. What does the relative frequency column in attached table  sum to?
  3. What is the difference between relative frequency and frequency for each data value  in the attached table?
  4. What is the difference between cumulative relative frequency and relative frequency  for each data value in attached table?

The correct answers are

  1. 65
  2. 1
  3. The relative frequency gives the relative proportion of each frequency in the sample while
  4. The frequency is the observed number of count of each grouping has in a given sample size

Step-by-step explanation:

1. The frequency column in the attached column sums up to 65 because it is the total number of sales persons selected

2. The relative frequency column in the attached table sum up to 1 because it is the sum of the fractions of the individual frequencies to the total frequency

3. The difference between relative frequency and frequency for each data value is that

The relative frequency gives the relative proportion of each frequency in the sample while

4. The frequency is the observed number of count of each grouping has in a given sample size

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Answer: 36

Step-by-step explanation:

One roll is of length = 9 feet

1 foot = 12 inches

9 feet = 12 *9 = 108 inches

Since there are 5 rolls

So, total length of 5 rolls = 108 * 5 = 540 inches

Since we are given that A seamstress needs to cut 15-inch pieces of ribbon from a roll of ribbon that is 9 feet in length.

We are supposed to find . What is the greatest number of 15-inch pieces the seamstress can cut from 5 of these rolls of ribbon

So, number of 15-inch pieces the seamstress can cut from 5 of these rolls of ribbon:

Hence the greatest number of 15-inch pieces the seamstress can cut from 5 of these rolls of ribbon is 36

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givi [52]

the factors of the term a^2+4a-5 are (a-1)(a+5)

Step-by-step explanation:

We need to find factors of the term: a^2+4a-5

For finding factors:

We need to break the middle term such that their product is equal to product of first and last term and their sum is equal to middle term

Breaking the middle term and finding factors:

a^2+4a-5

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=a(a+5)-1(a+5)

=(a-1)(a+5)

So, the factors of the term a^2+4a-5 are (a-1)(a+5)

Keywords: Finding factors

Learn more about finding factors at:

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