Answer:
I think copper
Explanation:
Material IACS % Conductivity
Silver 105
Copper 100
Gold 70
Aluminum 61
Nickel 22
Zinc 27
Brass 28
Iron 17
Tin 15
Phosphor Bronze 15
Lead 7
Nickel Aluminum Bronze 7
Steel 3 to 15
the table might help- your indian brother
<u>Answer:</u> The correct statement is B will give up two electrons to form bonds.
<u>Explanation:</u>
We are given:
Number of electrons in Atom A = 10
Number of electrons in Atom B = 12
Writing the electronic configuration for both the atoms:
For A: ![1s^22s^22p^6](https://tex.z-dn.net/?f=1s%5E22s%5E22p%5E6)
For B: ![1s^22s^22p^63s^2](https://tex.z-dn.net/?f=1s%5E22s%5E22p%5E63s%5E2)
From the configuration, it is clearly visible that the configuration of Atom A is stable and this atom will neither gain or loose electrons to attain stability.
Atom B has 2 valence electrons and by loosing these 2 electrons, it will attain stable electronic configuration and form
ion. Atom B will bond after loosing 2 electrons.
Hence, the correct statement is B will give up two electrons to form bonds.
Answer:
For example, propene reacts with aqueous chlorine to form 1-chloro-2-propanol as the major product.