Answer:
7560 Joules
Explanation:
= Mass of first car = 
= Mass of second car = 
= Initial Velocity of first car = 0.3 m/s
= Initial Velocity of second car = -0.12 m/s
v = Velocity of combined mass
As linear momentum of the system is conserved
Energy lost is
The Energy lost in the collision is 7560 Joules
Answer:
b. It is dropped
Explanation:
If the initial velocity is zero, the object move from rest. That happens if the object is dropped
Energy Density = 1/2 × ε(0) × (V/d)^2
V = 100, d = 0.01, ε(0) = 8.85 x 10^-12
Answer:
* The first thing we observe is that the frequency response does not change
* The current that circulates in the circuit decreases due to the new resistance at the resonance point,
Z = R + R₂
Explanation:
The impedance of a series circuit is
Z₀² = R² + (X_L-X_C) ²
when we place another resistor in series the initial resistance impedance changes to
Z² = (R + R₂) ² + (X_L - X_C) ²
let's analyze this expression
* The first thing we observe is that the frequency response does not change
* The current that circulates in the circuit decreases due to the new resistance at the resonance point,
Z = R + R₂
Kinetic energy lost in collision is 10 J.
<u>Explanation:</u>
Given,
Mass, 
= 4 kg
Speed, 
= 5 m/s
= 1 kg
= 0
Speed after collision = 4 m/s
Kinetic energy lost, K×E = ?
During collision, momentum is conserved.
Before collision, the kinetic energy is
By plugging in the values we get,
K×E = 50 J
Therefore, kinetic energy before collision is 50 J
Kinetic energy after collision:
Since,
Initial Kinetic energy = Final kinetic energy
50 J = 40 J + K×E(lost)
K×E(lost) = 50 J - 40 J
K×E(lost) = 10 J
Therefore, kinetic energy lost in collision is 10 J.
