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3 years ago

I hope you are able to read this question?? Help ASAP this question is on the quiz tommorow

Physics

1 answer:

Masteriza [31]3 years ago

8 0

You would be correct.

Because you have only JUST released the arrow, and how close he is to the target, it would have the same amount of energy when it strikes the target. Yes, the kinetic energy would be destroyed when you hit the target but not right away. And yes, the potential energy would also be destroyed once you release the arrow, but it goes straight back once it stops moving, aka when it hits the target, although it has only just stopped moving.

Hope this helps!

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If the specific latent heat of ice is 340 000 J/kg,

Ganezh [65]

Answer:

jsjdgsudgwid s

Explanation:

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2 years ago

How does momentum relate to impulse ?

fomenos

Answer:

C. Impulse = F*t=(m*a)*t= m*(a*t) = m*Dv= D(Momentum) (“D” here’s mean Delta so change in)

Explanation:

In fact, the impulse is equal to the change in momentum of an object.

Impulse is defined as the product between the force (F) and the time (t):

$I=Ft$

however, the force is defined as the product between mass (m) and acceleration (a):

$F=ma\\I=(ma)t$

But the product a (acceleration) times t (time) is equal to the change in velocity of the object:

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And this is exactly the definition of change in momentum:

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3 years ago

Choose all the right answers. Select five options.

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Answer:

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2 years ago

Read 2 more answers

If a gun is sighted to hit targets that are at the same height as the gun and 85 m away at the same height, how low, as a positi

Alex

If a gun is sighted to hit targets that are at the same height as the gun and 85 m away at the same height, how low, as a positive number in meters, will the bullet hit if aimed directly at a target 180 m away

The muzzle velocity of the bullet is 275 m/s

Answer:

y = -1.1109 m

Explanation:

Range = $\frac{v^2sin2\theta}{g}$

range = 85 m

velocity = 275 m/s

g = 9.8 m/s²

$85 = \frac{(275)^2sin2 \theta}{9.8}$

$833=(275)^2sin2\theta$

$833= 75625sin2\theta$

$0.01101 =sin2 \theta$

$0.005505 =sin \theta$

$\theta =sin^{-1}(0.005505)$

$\theta = 0.3154^0$

If the bullet is aimed at a target 180 m, time required to travel 180 m with horizontal component will be;

$t=\frac{180}{275cos0.3154}$

t = 0.6546 sec

To determine, how low as a positive number in meters.

$y=vyt-\frac{gt^2}{2}$

y = $275 sin(0.3154)*(0.6546)-$ $\frac{9.8*(0.6546)^2}{2}$

y = 0.9909 - 2.1018

y = -1.1109 m

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3 years ago

When would an atom act like a magnet?

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2 years ago