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hammer [34]
3 years ago
5

Emergency Need help in algebra fast

Mathematics
1 answer:
8_murik_8 [283]3 years ago
7 0

Answer:

y = -8/3x + 8

Step-by-step explanation:

y = -8/3(x - 3)

Distributing the -8/3 you get:

y = -8/3x + 8

(The -3 in (x - 3) cancels out the 3 in -8/3, therefore it creates 8 with the negative multiplying by a negative.)

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Find the 11th term of the arithmetic sequence. <br> a3 = 20.5 and a8 = 13, a11 = ______. ...?
lianna [129]
In order to solve for a nth term in an arithmetic sequence, we use the formula written as:<span>

an = a1 + (n-1)d

where an is the nth term, a1 is the first value in the sequence, n is the term position and d is the common difference.

First, we need to calculate for d from the given values above.  
<span>a3 = 20.5 and a8 = 13
</span>

an = a1 + (n-1)d
20.5 = a1 + (3-1)d

</span>an = a1 + (n-1)d
13 = a1 + (8-1)d
<span>
a1 = 23.5
d = -1.5

The 11th term is calculated as follows:

a11 = a1 + (n-1)d
a11= 23.5 + (11-1)(-1.5)
a11 = 8.5</span>
8 0
2 years ago
What is the relationship? Plzzz help it’s for right now
4vir4ik [10]

Answer:

B

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Which inequality is shown in the graph?
sergij07 [2.7K]

Answer:

The answer to your question is: letter C

Step-by-step explanation:

Data

Find the Parabola's equation and express the equation as an inequality.

Vertex = (0, -5)

Equation

                               (x- h) ² = 4p(y - k)

                               x² = y + 5

                              y = x² - 5

But, we need the area upper the parabola, then

                              y ≥ x² - 5

5 0
3 years ago
Can someone pls help??
Vlad1618 [11]

Answer:

a. The y coordinates for A are either 10 or -14

b.  The y coordinates for A are either -11 or 7

Step-by-step explanation:

distance = sqrt ((x2-x1)^2+(y2-y1)^2)

We know Point B and the x coordinate of point A as well as the distance

15 = sqrt ((-4-5)^2+(-2-y1)^2)

15 = sqrt ((-9)^2+(-2-y1)^2)

15 = sqrt (81+(-2-y1)^2)

Square each side

15^2 =sqrt (81+(-2-y1)^2)^2

225 =  81+(-2-y1)^2

Subtract 81 from each side

225-81 = 81-81 +(-2-y1)^2

144 = (-2-y1)^2

Take the square root of each side

±sqrt 144 = sqrt(-2-y1)^2

±12 = (-2-y1)

Add 2 to each side

2±12 = 2-2-y1

2±12 = -y1

14 = -y1  or -10 = -y1

Multiply by -1

-14 = y1  or 10 = y1

The y coordinates for A are either 10 or -14

Now move B to -7,-2

15 = sqrt ((-7-5)^2+(-2-y1)^2)

15 = sqrt ((-12)^2+(-2-y1)^2)

15 = sqrt (144+(-2-y1)^2)

Square each side

15^2 =sqrt (144+(-2-y1)^2)^2

225 =  144+(-2-y1)^2

Subtract 144 from each side

225-144 = 144-144 +(-2-y1)^2

81 = (-2-y1)^2

Take the square root of each side

±sqrt 81 = sqrt(-2-y1)^2

±9 = (-2-y1)

Add 2 to each side

2±9 = 2-2-y1

2±9 = -y1

11 = -y1  or -7 = -y1

Multiply by -1

-11 = y1  or 7 = y1

The y coordinates for A are either -11 or 7

3 0
3 years ago
Lines and triangles practices
Marianna [84]
<1 = 123
60 + 63 = 123
180 - 123 = 57
180 n- 57 = 123

Triangle angle-sum theorem
Alternate exterior angles theorem (?)
Same side interior angles theorem

idk what the last one is about sorry

hope this helps


4 0
3 years ago
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