The new mixture exists 56.5% peanuts.
<h3>How to estimate the total number of peanuts required for the mixture?</h3>
The first batch of 9 lb of mixed nuts possesses 40% peanuts.
This means the quantity of peanuts exists:
9 40/100 = 3.6 lb
The second batch of 9 lb of mixed nuts possesses 73% peanuts.
This means the quantity of peanuts exists:
9 73/100 = 6.57 lb
The total quantity of peanuts in the mix exists
3.6 lb + 6.57 lb = 10.17 lb
There exist 9 lb + 9 lb = 18 lb of mix.
Therefore, the percent of peanuts in the mix exists:
10.17 / 18 100 = 56.5%
The new mixture exists 56.5% peanuts.
To learn more about the total quantity refer to:
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Answer:
Sorry didnt mean to answer but which question do i need to solve
Step-by-step explanation:
How she probably are the answer is by and by her thinking that if you eat 1/2 since half is too she put two and she thought he could only to have the two slices maybe that's how did the error went but to the right as yours actually see so you are correct and she is wrong
We have different values asociated here, but easly we can also start
calculating the confidence level from a lower value.
We can define a confidence level of x%, then the asociated level of significance will be
Here for
Defining the p-value as 0.052 we have a range between the test reject,
that is,
, for the p-value
But when we do the calculation we note that if ; the test reject
That's mean that the asociated confidence interval won't contain 0.
Evaluating for the value of 90 and 94, 90 causes the hypothesis to be rejected immediately, but 94 does not.
The lowest number for this approximation in the response ranges should be the number immediately above 90%, that is, the answer is 94%.