1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
n200080 [17]
3 years ago
9

Starting from rest, a wheel with constant angular acceleration turns through an angle of 25 rad in a time t. What will its angul

ar velocity be after 3t?
Physics
1 answer:
alexandr402 [8]3 years ago
6 0

Answer:

θ = 225 rad

Explanation:

given data

angle = 25 rad

to find out

angular velocity after 3t?

solution

let angular acceleration α in t

θ = ω × t + 0.5 × α × t²        ........................1

here ω  = 0 (initial velocity )

so put this value here

25 = 0 + 0.5 × α × t²             ..........................2

α = 25 ÷ (0.5 t²)

α = 50 ÷ t²                            .........................3

now here we take in 3t

θ = ω × 3t + 0.5 × α × (3t)²

for ω  = 0

θ = 0 + 0.5 × α × 9t²

now put value in eq 2

so

θ = (0.5) ×  (50 ÷ t²) ×  (3t)²

θ = 25 × 9

θ = 225 rad

You might be interested in
A police officer is parked by the side of the road, when a speeding car travelling at 50 mi/hrpasses. The police car immediately
Blababa [14]

Answer:

a) time taken to catch up with speeding car is 12.25 secs

b) the police car will travel 273.8 m to catch up with the speeding car

Explanation:

Given that;

speed of car V_{c} = 50 mi/hr = 22.352 m/s

acceleration of police car = 10 mi/hr = 4.47 m/s²

V_{f}  = 70 mi/hr = 31.29 m/s

Now time taken to reach maximum speed is t₁

so

V_{f} =  V_{i} + at₁

we substitute

31.29 = 0 + 4.47t₁

t₁ = 31.29 / 4.47

t₁  = 7 sec

now

d₁ = 0 + 1/2 × at₁²

d₁ = 0 + 1/2 × 0 + 4.47×(7)²

d₁ = 109.5 m

so distance travelled by the speeding car in time t₁  will be

d_{c} = V_{c} × t₁

we substitute

d_{c} = 22.352 × 7

d_{c}  = 156.46 m

now distance between polive car and speeding car

Δd =  d_{c} - d₁

Δd = 156.46 - 109.5

Δd = 46.96 m

time taken to cover Δd will be

t₂ = Δd / ( V_{f} - V_{c} )

t₂ = 46.96 / ( 31.29 - 22.352 )

t₂ = 46.96 / 8.938

t₂ = 5.25 sec

distance travelled by the police in time t₂ will be

d₂ = V_{f} × t₂

d₂ = 31.29 × 5.25

d₂ = 164.3 m

a) How long will it take before the officer catches up to the speeding car;

time taken to catch up with speeding car;

t = t₁ + t₂

t = 7 + 5.25

t = 12.25 secs

Therefore, time taken to catch up with speeding car is 12.25 secs

b)  how far will it have travelled in order to do so;

distance = d₁ + d₂

distance = 109.5 + 164.3

distance = 273.8 m

Therefore, the police car will travel 273.8 m to catch up with the speeding car

6 0
3 years ago
A 6.0-kg object moving at 5.0 m/s collides with and sticks to a 2.0-kg object. After the collision the composite object is movin
gogolik [260]

Answer:

a) 23 m/s

Explanation:

  • Assuming no external forces acting during the collision, total momentum must be conserved, as follows:

       p_{o} = p_{f}  (1)

  • The initial momentum p₀, can be written as follows:

       p_{o} =  m_{1}  * v_{1o} + m_{2}* v_{2o} =   6.0 kg * 5.0 m/s + 2.0 kg * v_{2o}  (2)

  • The final momentum pf, can be written as follows:

        p_{f} = (m_{1} + m_{2} )* v_{f}  = 8.0 kg* (-2.0 m/s)  (3)

  • Since (2) and (3) are equal each other, we can solve for the only unknown that remains, v₂₀, as follows:

       v_{2o} = \frac{-6.0kg* 5m/s -8.0 kg*2.0m/s}{2.0kg}  = \frac{-46kg*m/s}{2.0kg} = -23.0 m/s  (4)

  • This means that the 2.0-kg object was moving at 23 m/s in a direction opposite to the 6.0-kg object, so its initial speed, before the collision, was 23.0 m/s.
6 0
3 years ago
Pls help thx need asap!!
torisob [31]

Answer:

10N right

Explanation:

First, we need to find the base of the triangle to find the force acting on the right of the object.

  • We have been given the hypotenuse and we need to find the adjacent, so we are using cos
  • SOH, CAH, TOA
  • cos(θ) = adjacent ÷ hypotenuse

Next, sub in the values (we don't know the adjacent so i've called it x):

  • cos(60) = x ÷ 60

To find x, we need to multiply both sides by 60

  • 60 × cos(60) = x
  • x = 30 N

Now we know all the forces, we can work out the net force:

  • Both of the 40N cancel out because they are opposite forces
  • The force on the right of the object is 10N stronger than the force on the left (30N - 20N), so the object would move to the right

8 0
3 years ago
HEEEEEEELLLLLLLPPPPP
Firdavs [7]

Answer:

the less shielding of electrons

6 0
3 years ago
A wire with a resistance of 20 is connected to a 12 battery. What is the current flowing through the wire?
Dima020 [189]
15.49 should be the answer if that is 12 watt battery.
3 0
3 years ago
Other questions:
  • A transformer has two sets of coils, the primary with N1 = 160 turns and the secondary with N2 = 1400 turns. The input rms volta
    11·1 answer
  • What is newstons 2nd law
    8·2 answers
  • Calorimetry what is the relationship between heat energy and temperature answer key
    5·1 answer
  • Why might there be a slight downslope in in the total energy instead of a flat constant?
    15·1 answer
  • A barge floating in fresh water (rho = 1000 kg/m3) is shaped like a hollow rectangular prism with base area A = 550 m2 and heigh
    11·1 answer
  • Explain the origin of earth's motion based on the origin of the galaxy and its solar system?
    5·1 answer
  • Technician A says that LCDs may be slow to work at low temperatures. Technician B says that an LCD dash display can be damaged i
    10·1 answer
  • 1
    8·1 answer
  • What is the function of the cardiovascular system?
    8·2 answers
  • How can we use magnetic fields to transport objects from one location to another?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!