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3 years ago

what is the equation of a line that is perpendicular to -x+7y=42 and goes through (-2,-1) in slope intercept form

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

7 0

Answer:

y = -7x - 15

Step-by-step explanation:

Perpendicular lines have negative reciprocal slopes

Given line

- x + 7y = 42

In slope-intercept form it is

- x + 7y = 42
7y = x + 42
y = 1/7x + 6

Perpendicular line has slope - 1/(1/7) = - 7 and its equation is:

y = - 7x + b

Finding b using the point (-2, -1)

-1 = -7(-2) + b
-1 = 14 + b
b = -1 - 14
b = -15

So the line is

y = -7x - 15

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what is the equation of a line that is perpendicular to -x+7y=42 and goes through (-2,-1) in slope intercept form​

what is the equation of a line that is perpendicular to -x+7y=42 and goes through (-2,-1) in slope intercept form