We are given the function:
g(x) = 6 (4)^x
Part A.
To get the average rate of change, we use the formula:
average rate of change = [g(x2) – g(x1)] / (x2 – x1)
Section A:
average rate of change = [6 (4)^1 – 6 (4)^0] / (1 – 0) =
18
Section B:
average rate of change = [6 (4)^3 – 6 (4)^2] / (3 – 2) =
288
Part B.
288 / 18 = 16
Therefore the average rate of change of Section B is 16 times
greater than in Section A.
<span>The average rate of change is greater between x = 2 to x = 3 than between
x = 1 and x = 0 because an exponential function's rate of change increases
with increasing x (not constant).</span>
Answer:
96 in²
Step-by-step explanation:
Lateral surface area
= 3 rectangles
(4×8) + (3×8) + (5×8)
32 + 24 + 40
96 in²
9.77 to the nearest tenths
first, find the number that is in the tenths place....it is 7....now look at the number directly to the right of it....if that number is 5 or greater, u would round that 7 up to an 8...but if that number is 4 or below, ur 7 would stay the same.
So the number directly to the right of 7 is 7...and since it is greater then 5, u have to round the 7 in the tenths place up to 8.
solution is : 9.8
2/5 = 8/20
3/4= 15/20
Therefore, 3/4 is larger than 2/5~
1x + 4y = 11 ⇒ 5x + 20y = 55
5x - 7y = -10 ⇒ <u>5x - 7y = -10</u>
<u>27y</u> = <u>65</u>
27 27
y = 2¹¹/₂₇
x + 4(2¹¹/₂₇) = 11
x + 8²²/₂₇ = 11
<u> - 8²²/₂₇ - 8²²/₂₇
</u> x = 2⁵/₂₇
(x, y) = (2⁵/₂₇, 2¹¹/₂₇)
