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Juliette [100K]
4 years ago
12

Write the point-slope form of the equation of the line through the given point with the given slope. (-5,0) slope= 2/3

Mathematics
1 answer:
amid [387]4 years ago
8 0

Answer:

Step-by-step explanation:

y - 0 = 2/3(x + 5)

y = 2/3x + 10/3

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What is the solution to 4x + 3 = 5 + x
dolphi86 [110]

Answer:

0.667

Step-by-step explanation:

subtract 1 x from both sides

3x+3=5

then subtract 3 from both sides

3x=2

then divide both sides by 3 to get x alone

Answer: O.66666 repeating and round

4 0
3 years ago
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Combine like terms, need help ASAP
Serga [27]

15. 7x^{4} - 5x^{4} = 2x^{4} \\17. 6b + 7b - 10 = 13b - 10\\19. y + 4 + 3 ( y + 2 ) = y + 4 + 3y + 6 = 4y + 10\\21. 3y^{2} + 3 ( 4y^{2} - 2 ) = 3y^{2} + 12y^{2} - 6 = 15y^{2} - 6\\23. 0.5 ( x^{4} - 3 ) + 12 = 0.5x^{4} - 1.5 + 12 = 0.5x^{4} + 10.5

8 0
3 years ago
14&gt;-2(2z+3)<br>please help me!!
Veseljchak [2.6K]

Answer:

14 > -2 (2z + 3)

First you need to distribute the -2 inside the parentheses.

14 > -2(2z) + -2(3)

14 > -4z - 6              -Add 6 to both sides of the equation

14 + 6 > -4z - 6 + 6

20 > -4z              -Now divide by -4 on both sides

20 / -4 > -4z / -4

-5 > z

However, when you divide by a negative number, you MUST flip the sign.

So, the answer is:

-5 < z

Hope this helps!


6 0
3 years ago
How much chocolate with each person get if 3 people share 1/2 lb of chocolate equally
Goshia [24]
Each person will get 1/6 of the chocolate
6 0
3 years ago
You are designing an open-top cylindrical container. The cylinder must have a volume of 81π cm3 . The bottom of the container mu
stira [4]

Answer:

Minimum dimensions are r=3cm, h=9cm

Minimum Cost=$254.47

Step-by-step explanation:

Volume of a Cylinder=πr²h

Volume of the Open Top Cylinder=81π cm³.

Therefore:

πr²h=81π

The bottom costs $3 per cm² and the side costs $1 per cm².

Total Surface Area of the open top Cylinder= πr²+2πrh

Cost, C=3πr²+2πrh

As the Volume is fixed.

πr²h=81π

r²h=81

h=81/r²

Modifying C,

C=3\pi r^{2}+2 \pi r \frac{81}{r^{2}}

C=3\pi r^{2}+ \frac{162 \pi}{r}

We differentiate C with respect to r

C'=6\pi r -\frac{162 \pi}{r^2}

At the minimum cost, C'=0.

Next we solve C'=0 for r

6\pi r -\frac{162 \pi}{r^2}=0

6πr³-162π=0

6πr³=162π

r³=27

r=3

The dimensions of the cylinder at minimum cost are therefore:

r=3 cm

h=81/9=9cm

The minimum cost of the Cylinder

C=3πr²+2πrh

=(3XπX3²)+(2XπX3X9)

=$254.47

8 0
4 years ago
Read 2 more answers
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