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3 years ago

9

Ariel earned a total of 180 dollars from drawing 12 identically-priced pictures at Friday's community meeting. Write an equation

to describe the relationship between "p", the number of pictures, and "e", the total earning. *

1 answer:

NeX [460]3 years ago

6 0

Answer:

e=12p

180=12*the number of the picture

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B.

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So you have to find the base of the trapezoid.

12 + 6 + 2 = 20

$\frac{12+20}{2} *6=96cm^2$

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Find the length of the tangent segment AB to the circles centered at O and O' whose radii are a and b respectively when the circ

bixtya [17]

Answer:

$AB=2\sqrt{ab}$

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From figure,

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In triangle $OO'D$

$(OO')^2=(OD)^2+(O' D)^2$

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3 years ago

A company makes traffic signs one of those signs can be modeled by an equilateral triangle with the perimeter of 144 inches the

barxatty [35]

Answer:

The height of the larger traffic signs is 51.96 inches

Step-by-step explanation:

Given that initially, A company makes traffic signs of an equilateral triangle with the perimeter of 144 inches

Now, A company makes similar traffic signs of perimeter 1.25 of original

New perimeter will be 1.25x144=180 inches

Let triangle ABC be a larger triangle with 180inches of the perimeter.

It is given that the triangle is an equilateral triangle,

Therefore, Side AB=BC=AC

The perimeter of a triangle ABC is

AB+BC+AC=180

3AB=180

AB=60 inches

Figure show that triangle ABC and AD is the height of the triangle.

Since, the triangle ABC is an equilateral triangle,

AD is the perpendicular bisector of BC

so that,

BD=DC and Angle ADB=90

In right triangle ADB,

Angle D =90 and Angle B =60

Side BD=60/2=30 inches and AB=60 inches

Using Pythagoras theorem,

$AD^{2} +BD^{2} =AC^{2}$

$(AD)^{2} +(30)^{2} =60^{2}$

$(AD)^{2} =60^{2}-(30)^{2}$

AD=51.96 inches

Thus, The height of the larger traffic signs is 51.96 inches

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3 years ago