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aliina [53]
3 years ago
10

In order to maintain a healthy weight, an average adult dog that weighs 16 kilograms must consume 11 grams of dog food per kilog

ram of its body weight each day. A specialty pet store sells dog food by the cup, where 4 cups of dog food weighs 412 grams. About how many cups of dog food should the dog consume each day in order to maintain a healthy weight?
Mathematics
1 answer:
Furkat [3]3 years ago
5 0
Approximately 1.7 cups because dog should consume 176 gram a day and one cup is 103 grams , so we just need to divide 176 on 103 and get 1.7 cups
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Evaluate 8.1p + 7.9r when p=7 and r=8
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119.9

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8 0
2 years ago
What is 49% of 849 ?
Sholpan [36]

Answer:

416.01

Step-by-step explanation:

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6 0
3 years ago
Please help me on this it’s due
olya-2409 [2.1K]
<h3>Answer:  5 cakes</h3>

================================================

Explanation:

Let's start off converting the mixed number 12 & 1/4 to an improper fraction.

a \frac{b}{c} = \frac{a*c+b}{c}\\\\12 \frac{1}{4} = \frac{12*4+1}{4}\\\\12 \frac{1}{4} = \frac{49}{4}\\\\

Do the same for the other mixed number 2 & 1/3.

a \frac{b}{c} = \frac{a*c+b}{c}\\\\2 \frac{1}{3} = \frac{2*3+1}{3}\\\\2 \frac{1}{3} = \frac{7}{3}\\\\

-----------------------

From here, we divide the two fractions. I converted them to improper fractions to make the division process easier.

\frac{49}{4} \div \frac{7}{3} = \frac{49}{4} \times \frac{3}{7}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{49\times 3}{4\times 7}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{7\times 7\times 3}{4\times 7}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{7\times 3}{4}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{21}{4}\\\\

The last step is to convert that result to a mixed number.

\frac{21}{4} = \frac{4*5+1}{4}\\\\\frac{21}{4} = \frac{4*5}{4}+\frac{1}{4}\\\\\frac{21}{4} = 4+\frac{1}{4}\\\\\frac{21}{4} = 5 \frac{1}{4}\\\\

Note that 21/4 = 5.25 and 1/4 = 0.25 to help check the answer.

-----------------------

Therefore, she can make 5 cakes. The fractional portion 1/4 is ignored since we're only considering whole cakes rather than partial ones.

3 0
3 years ago
Please help, I am super stuck and I cant lose points<br><br> this homework is 16 points total
bekas [8.4K]
Hello,

7)  A∪C={1,2,3,4,5,7,9}

8) A∩B={2,4}

C'= complement of C ={2,4,6}

9) A∪B∩C'={1,2,3,4,6,8}∩{2,4,6}={2,4,6}

10) A∪(B∩C')={1,2,3,4}∩{2,4,6}={1,2,3,4,6}

Are you blind?
4 0
3 years ago
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