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Lady_Fox [76]
3 years ago
15

True or false: in the water cycle, water returns to Earth as condesation, usually in the form of rain or snow.

Chemistry
2 answers:
german3 years ago
6 0
False, condensation is the cooling of steam.  Precipitation is the return of water to Earth.

ch4aika [34]3 years ago
3 0
False. Condensation forms the clouds, the way water returns to the earth is through precipitation. Hope this helps.
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What information does a net ionic equation give?
katen-ka-za [31]

Answer:

C. It lists only the substances that are changed.

Explanation:

Balanced Chemical equation:

HClO₂(aq) + NaOH(aq) → H₂O(l) + NaClO₂ (aq)

Ionic equation:

H⁺(aq) + ClO₂⁻(aq) + Na⁺(aq) + OH⁻(aq) → H₂O(l) + Na⁺(aq) + ClO₂⁻ (aq)

Net ionic equation:

H⁺(aq) + OH⁻(aq) → H₂O(l)  

The ClO₂⁻(aq) and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.  This'e why it is written in net ionic equation.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

3 0
3 years ago
Group VIlA elements are very active non metal​
igomit [66]

Explanation:

Halogens (group 17) are very reactive because they need only one electron to fulfil their noble gas configuration. That's what ...

8 0
3 years ago
Jane often make inferences what is an example of an inference she made about the chimpanzee
docker41 [41]

Answer:

the chimpanzee is a creepy creature because he's hairy

Explanation: it's true

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5 0
3 years ago
a 101 g piece of aluminum (aluminum = 0.900 J/g oC) is heated to 100.1 oC and added to 48.9 g of water at an initial temperature
vovikov84 [41]

Answer:

The final temperature of the mixture is = 42.14 °C

Explanation:

Mass of the aluminium m_{a} = 101 gm

Specific heat for aluminium C_{a} = 0.9 \frac{J}{gm c }

Temperature of aluminium T_{a} = 100.1 °C

Mass of water m_{w} = 48.9 gm

Specific heat for water C_{w} = 4.2 \frac{J}{gm c }

Initial temperature of water T_{w} = 16.5 °C

From energy balance principal when the aluminium piece is heated and dropped in to the water , the final temperature of aluminium & the water becomes equal.

From the energy conservation principal

Heat lost from the aluminium piece = heat gain by the water

⇒  m_{a} C_{a} ( T_{a} - T_{f} ) =  m_{w} C_{w} ( T_{f} - T_{w} ) ----------- (1)

Put all the values in equation (1)

⇒ 101 × 0.9 × (100.1 - T_{f} ) = 48.9 × 4.2 × ( T_{f} - 16.5 )

⇒ 90.9 × (100.1 - T_{f} ) = 205.38 × ( T_{f} - 16.5 )

⇒ 100.1 - T_{f} = 2.26 ( T_{f} - 16.5 )

⇒ 100.1 - T_{f} = 2.26 T_{f}  - 37.28

⇒ 3.26 T_{f} = 137.38

⇒ T_{f} = 42.14 °C

Therefore the final temperature of the mixture is = 42.14 °C

7 0
3 years ago
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