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vodka [1.7K]
4 years ago
5

Why do people bleed .-.

Physics
2 answers:
Maslowich4 years ago
5 0
Because the liver helps to regulate blood clotting
SashulF [63]4 years ago
3 0
Because the liver helps to regulate blood clotting, people<span> with liver disease (for example, hepatitis or cirrhosis) also have a tendency to </span>bleed<span> easily. Most commonly, easy or excessive bruising occurs because the skin and blood vessels are fragile.

Hope This Helped! :3</span>
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A hollow conducting sphere with an outer radius of 0.295 m and an inner radius of 0.200 m has a uniform surface charge density o
IrinaK [193]

Answer:

a. 6.032\times10^{-6}C/m^2

b.6.816\times10^5N/C

Explanation:

#Apply  surface charge density, electric field, and Gauss law to solve:

a. Surface charge density is defined as charge per area denoted as \sigma

\sigma=\frac{Q}{4\pi r_{out}^2}, and the strength of the electric field outside the sphere E=\frac{\sigma _{new}}{\epsilon _o}

Using Gauss Law, total electric flux out of a closed surface is equal to the total charge enclosed divided by the permittivity.

\phi=\frac{Q_{enclosed}}{\epsilon_o}\\\\\sigma=\frac{Q}{4\pi r_{out}^2}\\\\\sigma=\frac{0.370\times 10^{-6}}{4\pi \times (0.295m)^2}\\\\=3.383\times10^{-7}C/m^2  #surface charge outside sphere.

\sigma_{new}=\sigma_{s}-\sigma\\\\\sigma_{new}=6.37\times10^{-6}C/m^2-3.383\times10^{-7}C/m^2\\\\\sigma_{new}=6.032\times10^{-6}C/m^2

Hence, the new charge density on the outside of the sphere is 6.032\times10^{-6}C/m^2

b. The strength of the electric field just outside the sphere is calculated as:

From a above, we know the new surface charge to be 6.032\times10^{-6}C/m^2,

E=\frac{\sigma _{new}}{\epsilon _o}\\\\=\frac{6.032\times10^{-6}C/m^2}{\epsilon _o}\\\\\epsilon _o=8.85\times10^{-12}C^2/N.m^2\\\\E=\frac{6.032\times10^{-6}C/m^2}{8.85\times10^{-12}C^2/N.m^2}\\\\E=6.816\times10^5N/C

Hence, the strength of the electric field just outside the sphere is 6.816\times10^5N/C

5 0
3 years ago
What do we know about the relative strength of the electric field around each object?
Vsevolod [243]

Answer:

A charged object in an electric field experiences a force due to the field. The electric field strength, E, at a point in the field is defined as the force per unit charge on a positive test charge placed at that point.

Explanation:

6 0
3 years ago
Pls help!!<br> 1 example of a conductor and 1 example of a insulator in your EVERYDAY world.
satela [25.4K]

Answer:

Conductors:Aluminum, copper, car cables

Insulator: rubber, glass

6 0
3 years ago
How can non visible radiation be used
DanielleElmas [232]
Here are some popular applications of
non-visible electromagnetic radiation:

-- listen to the weather and music on the radio
-- watch a football game on TV
-- change the TV channel from the couch, using the 'remote'
-- make toast
-- warm leftover meatloaf in the "microwave"
-- make a call with your cellphone
-- text a friend with your 'smartphone'
-- surf the internet in your house without wires (with WiFi in the house)
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3 0
4 years ago
Read 2 more answers
A solid ball of mass M = 2.0 kg and radius R = 0.25 m starts from rest at a height h = 3.0 m above the bottom of the path. It ro
Lady bird [3.3K]

Answer:

6.48 m/s

Explanation:

We are given that

Mass,M=2 kg

Radius,R=0.25 m

Height,h=3 m

Moment of inertia of solid sphere=I=\frac{2}{5}MR^2

We have to find the linear speed.

\omega=\frac{v}{R}

By law of conservation of energy

mgh=\frac{1}{2}I\omega^2+\frac{1}{2}mv^2

mgh=\frac{1}{2}I(\frac{v}{R})^2+\frac{1}{2}mv^2=\frac{1}{2}v^2(\frac{I}{R^2}+m)

Where g=9.8m/s^2

Substitute the values

2\times 9.8\times 3=\frac{1}{2}(\frac{2}{5R^2}MR^2+M)=\frac{7}{10}Mv^2=\frac{7}{10}(2)v^2

v^2=\frac{2\times 9.8\times 3\times 10}{7\times 2}

v=\sqrt{\frac{2\times 9.8\times 3\times 5}{7}}

v=6.48m/s

5 0
3 years ago
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