Answer:
420J
Explanation:
Power is the time rate of change in energy. Power is the ratio of energy to time. The S.I unit of power is in watts.
Given that the flash lasts for 1/675 s, power output is 2.7 * 10⁵ W. Hence:
Power = Energy / time
Substituting:
2.7 * 10⁵ W = Energy / (1/675)
Energy = 2.7 * 10⁵ W * 1/675 = 400J
Therefore the energy emitted as light is 400J.
Since the conversion of electric energy to light is 95% efficient, hence the energy stored as electrical energy is:
Energy(capacitor) = 5% of 400J + 400J = 0.05*400 + 400
Energy(capacitor) = 420J
To solve this problem we will apply the concepts related to the calculation of the speed of sound, the calculation of the Mach number and finally the calculation of the temperature at the front stagnation point. We will calculate the speed in international units as well as the temperature. With these values we will calculate the speed of the sound and the number of Mach. Finally we will calculate the temperature at the front stagnation point.
The altitude is,
And the velocity can be written as,
From the properties of standard atmosphere at altitude z = 20km temperature is
Velocity of sound at this altitude is
Then the Mach number
So front stagnation temperature
Therefore the temperature at its front stagnation point is 689.87K
Answer:
What is the definition magnitude?
Magnitude (mathematics), a measure of the size of a mathematical object.
xXxAnimexXx
Have a great day!
Answer:
P = 2 pi (L / g)^1/2
P2 / P1 = (8 / 2)^1/2 = 2
The period would be twice as long or 5.6 sec.
Answer:
9/25
Explanation:
Distance covered in the first 5 seconds:
Δx = v₀ t + ½ at²
Δx₀₋₅ = (0) (5) + ½ a (5)²
Δx₀₋₅ = 25a/2
Distance covered in the first 4 seconds:
Δx = v₀ t + ½ at²
Δx₀₋₄ = (0) (4) + ½ a (4)²
Δx₀₋₄ = 8a
So the distance covered during the 5th second is:
Δx₅ = 25a/2 − 8a
Δx₅ = 9a/2
So the ratio of the distance covered during the 5th second to the distance covered in the first 5 seconds is:
Δx₅ / Δx₀₋₅
(9a/2) / (25a/2)
9/25
