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Stolb23 [73]
3 years ago
12

When less force is used but the amount of work done remains the same, how does distance change?

Physics
1 answer:
Nostrana [21]3 years ago
3 0
Work is the product of force and distance, or W=F*x. The work remains the same, but there is less force. There must be an increase in distance to maintain the stability of work, which is choice B
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Answer:

C

Explanation:

it transforms electrical energy into mechanical energy.

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What is the total energy equation?
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A toolbox of mass 3.2kg is lowered by a rope from the roof to the ground. Find the acceleration of the toolbox when the force of
Lisa [10]

Answer:

The answer to your question is:

a) 2.7 m/s²

b) -3.6 m/s²

Explanation:

Data

mass of the toolbox = 3.2 kg

a = ?

F = 40 N and F = 20 N

g = 9.81 m/s²

Formula

Second law of motion = F = ma

                              a + g = F / m

                              a = F/m - g

a)                            a = 40/3.2 - 9.81

                              a = 2.69 ≈ 2.7 m/s²   positive up

b)                            a = 20/ 3.2 - 9.81

                              a = 6.25 - 9.81

                                  = - 3.56 ≈ - 3.6 m/s²  negative down

8 0
3 years ago
A 2,200-kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls 3.40 m before coming into contact
love history [14]

Answer:

The magnitude of Force is 8.58×10⁵N and direction is upwards

Explanation:

The work beam does on the pile driver is given by

W=(FCos180°)Δx= -F(0.088m)

From work energy theorem

W_{nc}=(KE_{f}-KE_{i})+(PE_{f}-PE_{i})\\W_{nc}=1/2m(vf^{2}-vi^{2})+mg(yf-yi)

Choosing y=0 at the the level where the driver first contacts the beam and vi=0 at yi=+3.40m and comes to rest again vf=0 at yf= -0.088m

So

-F(0.088m)=1/2m(0-0)+2,200kg(9.81m/s^{2} )(-0.088m-3.40m)\\-F(0.088)=-75508.224\\F=75508.224/0.088\\F=8.58*10^{5} N

The magnitude of Force is 8.58×10⁵N and direction is upwards

6 0
3 years ago
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