Answer:
<em>600N(downwards)</em>
Explanations
<em>600N(downwards)</em>
Mas of the person = 60kg
Acceleration due to gravity = -10m/s²
To get the earths pull on the person, we will use the Newton second law of motion;
Force = mass * acceleration;
Force = 60 * -10
Force- -600N
<em>Hence the earth gravitational pull on the person is 600N(downwards). It is downwards due to the negative sign.</em>
<em></em>
Answer
given,
time = 10 s
ship's speed = 5 Km/h
F = m a
a is the acceleration and m is mass.
In the first case
F₁=m x a₁
where a₁ = difference in velocity / time
F₁ is constant acceleration is also a constant.
Δv₁ = 5 x 0.278
Δv₁ = 1.39 m/s
a₁ = 0.139 m/s²
F₂ =m x a₂
F₃ = F₂ + F₁
Δv₃ = 19 x 0.278
Δv₃ = 5.282 m/s
a₃=Δv₂ / t
a₃ = 0.5282 m²/s
m a₃=m a₁ + m a₂
a₃ = a₂ + a₁
0.5282 = a₂ + 0.139
a₂=0.3892 m²/s
F₂ = m x 0.3892...........(1)
F₁ = m x 0.139...............(2)
F₂/F₁
ratio = 
ratio = 2.8
If <em>A</em> = <em>i</em> - <em>j</em> + <em>k</em>, then the magnitude of <em>A</em> is
||<em>A</em>|| = √(1² + (-1)² + 1²) = √3
Then the unit vector in the direction of <em>A</em> is 1/||A|| multiplied by <em>A</em> :
<em>u</em> = <em>A</em>/||<em>A</em>|| = (<em>i</em> - <em>j</em> + <em>k</em>)/√3
(choice D)
<h2><em>the correct answer is </em></h2><h2><em>A) 111.36 seconds</em></h2><h2><em>HOPE IT HELPS (◕‿◕✿) </em></h2>
