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Doss [256]
3 years ago
10

A 15kg penguin slips on a wet rock (rip I hope he's okay). The coefficient of friction between the penguin and the rock is .250.

What frictional force impedes the penguins motion? I NEED THE EQUATION AND THE SOLUTION PLEASE
Physics
1 answer:
Marina86 [1]3 years ago
8 0
That poor penguin :( so frictional force = coefficient*normal force. 15*9.8=147=normal force so 147*0.25=36.75=frictional force. And I'm pretty sure you would use the static coefficient as the question doesn't say the the penguin is already slipping, he slips (assuming he has just taken a step).
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A horizontal pipe of inner diameter 2.2 cm carries water with a density of 1000.0 kg/m3 flowing at a rate of 1.5 kg/s. If the pi
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The speed of the water in the wider part will be 1.194 m/sec. Speed is a time-based quantity. Its SI unit is m/sec.

<h3> What is speed?</h3>

Speed is defined as the rate of change of the distance or the height attained.

The given data in the problem is;

The initial diameter is,\rm d_1 = 2.2 \ cm

initial radius,

r_1 = \frac{d_1}{2} \\\\ r_1 = \frac{2.2}{2} \\\\ r_1 = 1.1\ cm

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The speed of the water in the wider part will be;

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\rm A_1 V_1 = A_2V_2  \\\\\ 3.8 \times 10^{-4} \times 3.947 = 12.56 \times 10^{-4} \times V_2 \\\\ V_2= 1.194 \ m/sec

Hence, the speed of the water in the wider part will be 1.194 m/sec.

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brainly.com/question/7359669

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7 0
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When a submarine dives to a depth of 5.0 × 102 m, how much pressure, in pa, must its hull be able to withstand? how many times l
nordsb [41]
<span>Depth = 5.0 Ă— 10^2 m
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