Answer:
H3PO4 + 5HCl → PCl5 + 4H2O
Explanation:
The speed of the water in the wider part will be 1.194 m/sec. Speed is a time-based quantity. Its SI unit is m/sec.
<h3> What is speed?</h3>
Speed is defined as the rate of change of the distance or the height attained.
The given data in the problem is;
The initial diameter is,
initial radius,

The initial crossection area;

The final crossection area;

The initial flow rate is;
R = density ×velocity ×area

The speed of the water in the wider part will be;
From the continuity equation;

Hence, the speed of the water in the wider part will be 1.194 m/sec.
To learn more about the speed, refer to the link;
brainly.com/question/7359669
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<span>Depth = 5.0 Ă— 10^2 m
Density of sea water = 1.025 x 10^3
Pd = Po + pgh
Atmospheric pressure is standard Patm = 1.01325 x 10^5 Pa
Since the normal pressure is retained in the hull, no need to bother about Po
Pd = pgh = 1.025 x 10^3 x 9.8 x 5.0 x 10^2 = 50.225 x 10^5
So now Pd / Patm = 50.225 x 10^5 / 1.01325 x 10^5 = 49.56
So it is 49.56 times larger.</span>
Water boiling, no cheamical bonds have been altered.
Hello, love! The answer is True, or T, on Edge2020.
Hope this helped!
~ V.