Answer:
<h2> v= 21.47m/s </h2>
Explanation:
For the car to turn at the about the centripetal force must not be greater than the static friction between the tires and the road
we will use the expression relating centripetal force and static friction below
let U represent the coefficient of static friction
Given that
U= 0.50
mass m= 1200-kg
radius r= 94.0 m
Assuming g= 9.81 m/s^2
substituting our given data in to expression we can solve for the speed V
making v the subject of formula we have
v= 21.47m/s
<em><u>hence the maximum velocity of the car is 21.47m/s</u></em>
Answer:
I think its b lol correct me if I'm wrong
I think the answer is periodic motion.
Answer:
750 nm
Explanation:
= separation of the slits = 1.8 mm = 0.0018 m
λ = wavelength of monochromatic light
= screen distance = 4.8 m
= position of first bright fringe = 
= order = 1
Position of first bright fringe is given as
λ = 7.5 x 10⁻⁷ m
λ = 750 nm
Answer:
0.54m
Explanation:
Step one:
given data
length of seesaw= 3m
mass of man m1= 85kg
weight = mg
W1= 85*10= 850N
mass of daughter m2= 35kg
W2= 35*10= 350N
distance from the center= (1.5-0.2)= 1.3m
Step two:
we know that the sum of clockwise moment equals the anticlockwise moment
let the distance the must sit to balance the system be x
taking moment about the center of the system
350*1.3=850*x
455=850x
divide both sides by 850
x=455/850
x=0.54
Hence the man must sit 0.54m from the right to balance the system
