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mixer [17]
3 years ago
6

A car moving with a velocity of 20 meters/second has

Physics
1 answer:
kenny6666 [7]3 years ago
5 0
Kinetic energy is the energy of an object in motion. It is expressed as the product of its mass and the square of its velocity. The opposite of this energy is called the potential energy, the energy of an object at rest. Calculations are as follows:
<span>
KE = mv^2
</span><span>1.8x10^5 J = m(20 m/s)^2
</span><span>m = 450 kg</span>
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Please help me out with this.
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We have that Gravity a force acting down ward against any object and frictional force is a force acting a against  movement, Hence

  • True
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<h3>Gravity and frictional force</h3>

Generally, Gravity a force acting down ward against any object on earth at an acceleration of about  9.8m/s

and frictional force is a force acting a against the movement based on contact with another surface

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3 years ago
Rocks that are formed as a result of deposits from weathering and erosion
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<h2>Answer: Sedimentary rocks </h2>

Sedimentary rocks are formed from sediments and deposits of particles of various types, forms and sizes that are transported by air, wind or water, and then subjected to chemical processes to become rocks.

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8 0
3 years ago
"Two electrons in an atom are separated by 1.4 × 10−10 m, the typical size of an atom. What is the force between them? The Coulo
Rudiy27

Answer:

F\approx 1.17551\times 10^{-8} N

Explanation:

In order to find the force between the two electrons, we need to use Coulomb's law. In its scalar form, the law is given by:

F=k_c \frac{q_1*q_2}{r^2}

Where:

k_c=Coulomb\hspace{3}constant\approx 9\times10^{9} \frac{Nm^2}{C^2} \\q_1\hspace{3}and\hspace{3}q_2=Magnitudes\hspace{3}of\hspace{3}the\hspace{3}charges\\r=Distance\hspace{3}between\hspace{3}the\hspace{3}charges

The electric charge of an electron is a known constant given by:

q_e \approx -1.6 \times 10^{-19} C

So:

q_1=q_2=q_e \approx -1.6 \times 10^{-19} C

Therefore, replacing the data provided in the Coulomb's law equation:

F=(9\times 10^{9})\frac{(-1.6\times 10^{-19})*(-1.6\times 10^{-19})}{(1.4\times 10^{-10})^2} =1.175510204\times10^{-8} \approx 1.17551\times10^{-8}N

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