A car moving with a velocity of 20 meters/second has
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Answer:
The magnitude of the net force is √2F.
Explanation:
Since the two particles have the same charge Q, they exert the same force on the test charge; both attractive or repulsive. So, the angle between the two forces is 90° in any case. Now, as we know the magnitude of these forces and that they form a 90° angle, we can use the Pythagorean Theorem to calculate the magnitude of the resultant net force:
Then, it means that the net force acting on the test charge has a magnitude of √2F.
Answer:
Explanation:
Given that:
mass of stone (M) = 0.100 kg
mass of bullet (m) = 2.50 g = 2.5 ×10 ⁻³ kg
initial velocity of stone () = 0 m/s
Initial velocity of bullet () = (500 m/s)i
Speed of the bullet after collision () = (300 m/s) j
Suppose we represent to be the velocity of the stone after the truck, then:
From linear momentum, the law of conservation can be applied which is expressed as:
∴
The magnitude now is:
Using the tangent of an angle to determine the direction of the velocity after the struck;
Let θ represent the direction: