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2 years ago

9

A skier stands at the top of a 50 meter slope. He then skis down the slope. What is his approximate speed at the bottom of the s

lope?

1 answer:

dedylja [7]2 years ago

7 0

Answer:

31 m/s

Explanation:

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What are the four main spheres of the earths ststem

vladimir2022 [97]

Answer:

"lithosphere" (land), "hydrosphere" (water), "biosphere" (living things), and "atmosphere" (air)

Hope this helps

-Amelia

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3 years ago

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Calculate the total resistance in a parallel circuit made up of resistances of 2Ω, 3Ω, and 4Ω. (Hint: When converting to a decim

natta225 [31]

Answer:

Total resistance = 0.92Ω

Explanation:

For parallel connected resistors we have effective resistance

$\frac{1}{R_{eff}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+.....$

Here parallel circuit made up of resistances of 2Ω, 3Ω, and 4Ω.

That is

R₁ = 2Ω

R₂ = 3Ω

R₃ = 4Ω

Substituting

$\frac{1}{R_{eff}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}\\\\\frac{1}{R_{eff}}=\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\\\\\frac{1}{R_{eff}}=\frac{6+4+3}{12}\\\\R_{eff}=\frac{12}{13}=0.92ohm$

Total resistance = 0.92Ω

6 0

3 years ago

A 49.5 gram super ball traveling at 25.5 m/s bounces off a brick wall and rebounds at 19.5 m/s. a high-speed camera records this

OLga [1]

T = 4.25 ms = 4 x 10⁻³ s, the time for rebound
v₁ = 25.5 m/s, the impacting velocty
v₂ = -19.5 m/s, the rebounding velocity (n the opposite directon)

The change in velocity is
v₂ - v₁ = - (25.5+19.5) = -45 m/s

The acceleration is
a = (-45 m/s)/(4 s) = -11.25 m/s²
The negative sign indicates that the final velocity is opposiye to the impact velocty.

Answer: The magnitude of the acceleration is 11.25 m/s²

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3 years ago

A segment of DNA that codes for the ability to make one type of protein molecule is known as a(n)____________________. A) axon B

astraxan [27]

The answer is C) Gene

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3 years ago

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For the wave of light you generated in the Part B, calculate the amount of energy in 1.0 mol of photons with that same frequency

Angelina_Jolie [31]

Answer:

2.7 J

Explanation:

The energy of one photon is given by

$E=hf$

where

h is the Planck constant

f is the frequency

For the photons in this problem,

$f=6.8\cdot 10^9 Hz$

So the energy of one photon is

$E_1=(6.63\cdot 10^{-34})(6.8\cdot 10^9 )=4.5\cdot 10^{-24} J$

The number of photons contained in 1.0 mol is

$N_A = 6.022\cdot 10^{23} mol^{-1}$ (Avogadro number)

So the total energy of $N_A$ photons contained in 1.0 mol is

$E=N_A E_1 =(6.022\cdot 10^{23})(4.5\cdot 10^{-24})=2.7 J$

3 0

3 years ago