Answer:
Explanation:
Given
wavelength of emissions are
Energy is given by
where h=Planck's constant
x=velocity of Light
=wavelength of emission
frequency corresponding to this emission
Energy corresponding to
frequency corresponding to this emission
Answer:
29274.93096 m/s
Explanation:
= Distance at perihelion =
= Distance at aphelion =
= Velocity at perihelion =
= Velocity at aphelion
m = Mass of the Earth = 5.98 × 10²⁴ kg
M = Mass of Sun =
Here, the angular momentum is conserved
Earth's orbital speed at aphelion is 29274.93096 m/s
Kinetic energy is given by
Kinetic energy at perihelion is
Potential energy is given by
Potential energy at perihelion is
Kinetic energy at aphelion is
Potential energy is given by
Potential energy at aphelion is
Answer:
the light emitting must be of greater wavelength
Explanation:
For this exercise we must use the Planck equation
E = h f
And the speed of light
c = λ f
f = c / λ
We replace
E = h c / λ
The wavelength of the green light is of the order of 500 nm, let's calculate the energy
E = 6.63 10⁻³⁴ 3 10⁸ /λ
E = 1,989 10⁻²⁵ /λ
λ = 500 nm = 500 10⁻⁹ m
E = 1,989 10⁻²⁵ / 500 10⁻⁹
E = 3,978 10⁻¹⁹ J
That is the energy of the transition for a transition is an intermediate state the energy must be less, this implies that the wavelength must increase. For the explicit case of a state with half of this energy
= E / 2
= 3,978 10⁻¹⁹ / 2 = 1,989 10⁻¹⁹
Let's clear and calculate
λ = h c / E
λ = 1,989 10⁻²⁵ / 1,989 10⁻¹⁹
λ = 1 10⁻⁶ m
Let's reduce to nm
λ = 1000 nm
This wavelength is in the infrared region
the light emitting must be of greater wavelength