What’s the power if a student does 2240j of work for 2.8 seconds
1 answer:
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Answer:
Explanation:
From the given information:
radius = 15 m
Time T = 23 s
a) Speed (v) =
v = 4.10 m/s
b) The magnitude of the acceleration is:
a = 1.12 m/s²
c) True weight = mg
Apparent weight = normal force
From the top;
the normal force = upward direction,
weight is downward as well as the acceleration.
true weight - normal force = ma
apparent weight =mg - ma
= 0.886 m/s²
d)
From the bottom;
acceleration is upward, so:
apparent weight - true weight = ma
apparent weight = true weight + ma
= 1.114 m/s²