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matrenka [14]
4 years ago
15

What is the best definition for combining like terms

Mathematics
1 answer:
uysha [10]4 years ago
8 0

Step-by-step explanation:

Combing like terms means that you combine the terms that are alike. So, if you have integers you would combine the integers. If you had a variable like x, you would combine everything with x. For instance, 2x+4+3+7x, to combine like terms add 4+3 and 2x+7x.

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How many ways can you make change for .55 cents using only nickels, dimes and quarters
lora16 [44]

Answer:

A few ways are:

2 quarters and a nickel

5 dimes and a nickel

1 quarter and 3 dimes

11 nickels


6 0
3 years ago
X + 5y = 8<br> -x + 2y = -1<br> How is this solved?
Oksi-84 [34.3K]
Add both the equations together to eliminate x

x+5y=8
-x+2y=-1

7y=7
y=1

Now fill in y into the original equation

x+5(1)=8
x+5=8
x=3

Now you can check by filling x and y into the second equation.

-(3)+2(1)=-1
-3+2=-1
-1=-1

So your answer will be (3, 1)

Brainliest my answer if it helps you out?
8 0
3 years ago
Read these sentences from the text.
chubhunter [2.5K]

Answer: Hi! I would say it is D because the other answers really don’t make sense. And the passages said that they were rated low for air quality.

Step-by-step explanation:

I hope this helps!

3 0
3 years ago
Points A, B and C make the triangle triangle ABC and are at the coordinates A(- 4, 3) , B(- 48, 17) and C(22, - 53) . Point D is
Nina [5.8K]

The equation of the median in standard form is; 9y - 38x = 179.

<h3>What is the equation of the media in standard form?</h3>

It follows from the task content that the point D is the midpoint of segment BC; Hence, the coordinates of point D given the coordinates of B and C above are given as; D(-13, -35).

The equation of the median which is the line joining points A and D is therefore determined as follows;

Slope = (-35-3)/(-13-(-4)) = 38/9

38/9 = (y-3)/(x+4)

9y -27 = 38x + 152

9y - 38x = 179.

Read more on equation of a line;

brainly.com/question/18831322

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6 0
2 years ago
please help me, Prove a quadrilateral with vertices G(1,-1), H(5,1), I(4,3) and J(0,1) is a rectangle using the parallelogram me
mestny [16]

Answer:

Step-by-step explanation:

We are given the coordinates of a quadrilateral that is G(1,-1), H(5,1), I(4,3) and J(0,1).

Now, before proving that this quadrilateral is a rectangle, we will prove that it is a parallelogram. For this, we will prove that the mid points of the diagonals of the quadrilateral are  equal, thus

Join JH and GI such that they form the diagonals of the quadrilateral.Now,

JH=\sqrt{(5-0)^{2}+(1-1)^{2}}=5 and

GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5

Now, mid point of JH=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

=(\frac{5+0}{2},\frac{1+1}{2})=(\frac{5}{2},1)

Mid point of GI=(\frac{5}{2},1)

Since, mid point point of JH and GI are equal, thus GHIJ is a parallelogram.

Now, to prove that it is a rectangle, it is sufficient to prove that it has a right angle by using the Pythagoras theorem.

Thus, From ΔGIJ, we have

(GI)^{2}=(IJ)^{2}+(JG)^{2}                             (1)

Now, JI=\sqrt{(4-0)^{2}+(3-1)^{2}}=\sqrt{20} and GJ=\sqrt{(0-1)^{2}+(1+1)^{2}}=\sqrt{5}

Substituting these values in (1), we get

5^{2}=(\sqrt{20})^{2}+(\sqrt{5})^{2} }

25=20+5

25=25

Thus, GIJ is a right angles triangle.

Hence, GHIJ is a rectangle.

Also, The diagonals GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5  and HJ=\sqrt{(0-5)^2+(1-1)^2}=5 are equal, thus, GHIJ is a rectangle.

6 0
3 years ago
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