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GrogVix [38]
3 years ago
15

???whats the answers

Mathematics
1 answer:
Aleks04 [339]3 years ago
3 0
11, 3, -3, -12
Hope this helps :)
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Write the quadratic function in vertex form.<br><br> y = x2 - 2x + 5
Jlenok [28]
Vertex form formula: y = a(x-h)^2 +k, with vertex (h,k)
There are multiple ways to find the vertex. One way is to find the roots and then find the x value exactly in between them, because this parabola is symmetrical. 

0 = (x - 3)(x + 2), so x = 3 and -2. The point directly in the middle is x = 1/2 = h 

To find the y value of the vertex, plug in 1/2 to the equation.

(1/2)^2 - 2(1/2) + 5 = 4.25 = k

y = (x - 0.5)^2 + 4.25
4 0
3 years ago
Read 2 more answers
The radius of a circle is 1 foot. What is the circle's area?
nikdorinn [45]

Answer:

3.14ft²

Step-by-step explanation:

Area of a circle= πr²

= 3.14 x 1²

= 3.14 x 1

= 3.14 ft²

8 0
3 years ago
F(x) = -x² + 4x - 1 find the value of f(x) if x = 0
ollegr [7]

Answer:

-1

Step-by-step explanation:

Given,

f(x) = -x² + 4x - 1 and x = 0

Putting the value of x we get,

f(0)= -0^{2} + (4 X 0) - 1

    = -0+0-1

    =-1

∴f(x)= -1

So, the required value is -1

8 0
2 years ago
13.1: Equivalent Expressions
scoundrel [369]

Distributive Property:  a ( b + c) = (a*b) + (a*c)

b)   x(x + 9) =  x*x + 9*x

               = x² + 9x    

c)  x² - 18x

     x² = x * x

  18x  = 18 *x

G C F = x

Greatest common factor in both the terms is 'x'.Take the common variable from both the terms.

x² - 18x = x*x - 18*x

            = x (x - 18)

           

Standard form.                Factored form

      x²                                     x*x

x²  +  9x                             x(x +9)

    x² - 18x                           x(x - 18)  

-x² + 10x                             x(-x + 10) = x(10 -x)

-x² - 2.75x                          -x(x + 2.75)

3 0
2 years ago
Which values are solutions to the inequality below? Check all that apply <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%7D%20"
MaRussiya [10]
X > 169 is your Answer thus: b:/d & f:
5 0
3 years ago
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