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uranmaximum [27]
3 years ago
14

What mass (g) of barium iodide is contained in 188 ml of a barium iodide solution that has an iodide ion concentration of 0.532m

19.6 39.1 19,600 39,100 276
Chemistry
1 answer:
Katarina [22]3 years ago
8 0

Answer:

What mass (g) of barium iodide is contained in 188 mL of a barium iodide solution that has an iodide ion concentration of 0.532 M?

A) 19.6

B) 39.1

C) 19,600

D) 39,100

E) 276

The correct answer to the question is

B) 39.1  grams

Explanation:

To solve the question

The molarity ratio is given by

188 ml of 0.532 M solution of iodide.

Therefore we have number of moles = 0.188 × 0.532 M = 0.100016 Moles

To find the mass, we note that the Number of moles = \frac{Mass}{Molar Mass} from which we have

Mass = Number of moles × molar mass

Where the molar mass of Barium Iodide = 391.136 g/mol

= 0.100016 moles ×391.136 g/mol = 39.12 g

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Details:

To write a balanced chemical equation we have to know formula units of compounds or molecules

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ammonium phosphate : (NH₄)₃PO₄

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Now to write a chemical equation

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So the Reaction will be

                      (NH₄)₃PO₄ + Al(NO₃)₃ -----------→  AlPO₄ + NH₄NO₃

Now balance the Chemical equation

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