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2 years ago

How many mL of 2.5 M K2SO4 are required to obtain 1.25 grams of the compound?

Chemistry

1 answer:

saul85 [17]2 years ago

6 0

2.87mL of 2.5 M K2SO4 are required to obtain 1.25 grams of the compound.

<h3>HOW TO CALCULATE VOLUME?</h3>

The volume of a substance can be calculated by dividing the number of moles of the substance by its molarity. That is;

volume = no. of moles ÷ molarity

According to this question, 2.5M K2SO4 are required to obtain 1.25 grams of the compound. The volume can be calculated as follows:

Molar mass of K2SO4 = 174.26 g/mol

moles of K2SO4 = 1.25g ÷ 174.26g/mol

moles of K2SO4 = 0.00717moles

Volume = 0.00717moles ÷ 2.5

Volume = 0.00287 L = 2.87mL.

Therefore, 2.87mL of 2.5 M K2SO4 are required to obtain 1.25 grams of the compound.

Learn more about volume at: brainly.com/question/1578538

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