Of Uranium-235 remains after 2.8 x 10^9 years, what was the original mass of the sample of Uranium-235? The half-life of Uranium-235 is 7.0 x 10^8 years. Uranium-232 has a half life of 68.8 years.
Answer:
V = 34.3 L
Explanation:
Given data:
Volume of hydrogen produced = ?
Mass of magnesium = 36.7 g
Temperature and pressure = standard
Solution:
Mg + 2HCl → MgCl₂ + H₂
Number of moles of magnesium:
Number of moles = mass/molar mass
Number of moles = 36.7 g/ 24 g/mol
Number of moles = 1.53 mol
Now we will compare the moles of magnesium with hydrogen.
Mg : H₂
1 : 1
1.53 : 1.53
Number of moles of hydrogen produced = 1.53 mol
Volume of hydrogen:
PV = nRT
V = nRT / P
V = 1.53 mol × 0.0821 atm.L/mol.K × 273 K/ 1 atm
V = 34.3 L
Answer:
324.554 K
Explanation:
Which can be converted back to °C by subtracting 273
Once again thus answer can be found using the gas law P1/T1 =P2/T2
Remember to convert to Kelvin before doing the calculations by adding 273
Answer:
5 moles of Fe₂(SO₄)₃ will be produced
Explanation:
Given data:
Number of moles of Fe₂(SO₄)₃ = ?
Number of moles of Fe react = 10 mol
Solution:
Chemical equation:
3H₂SO₄ + 2Fe → Fe₂(SO₄)₃ + 3H₂
Now we will compare the moles of iron and Fe₂(SO₄)₃ .
Fe : Fe₂(SO₄)₃
2 : 1
10 : 1/2×10 = 5 mol
5 moles of Fe₂(SO₄)₃ will be produced.