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Elanso [62]
3 years ago
8

To what does the term register refer in describing sound?

Physics
1 answer:
Citrus2011 [14]3 years ago
5 0
The pitch of the sound describes its highness or lowness. ... Register refers to a particular range of pitches that an instrument can reach. For example, an instrument can be played in its lower or upper register. The lower register producing lower pitches and the upper register producing higher pitches.
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How are the ways in which the pluton and pegmatite minerals form similar?
Rasek [7]
There both minerals and there both
8 0
4 years ago
​Determine usando ecuación de Bernoulli la Presión P1 necesaria para mantener la condición mostrada dentro del sistema mostrado
Amanda [17]

Answer:

PlROCA

Explanation:

6 0
3 years ago
A high-jumper, having just cleared the bar, lands on an air mattress and comes to rest. Had she landed directly on the hard grou
Hoochie [10]

Answer:

e. the air mattress exerts the same impulse, but a smaller net avg force, on the high-jumper than hard-ground.

Explanation:

This is according to the Newton's second law and energy conservation that the force exerted by the hard-ground is more than the force exerted by the mattress.

The hard ground stops the moving mass by its sudden reaction in the opposite direction of impact force whereas the mattress takes a longer time to stop the motion of same mass in a longer time leading to lesser average reaction force.

<u>Mathematical expression for the Newton's second law of motion is given as:</u>

F=\frac{dp}{dt} ............................................(1)

where:

dp = change in momentum

dt = time taken to change the momentum

We know, momentum:

p=m.v

Now, equation (1) becomes:

F=\frac{d(m.v)}{dt}

<em>∵mass is constant at speeds v << c (speed of light)</em>

\therefore F=m.\frac{dv}{dt}

and, \frac{dv}{dt} =a

where: a = acceleration

\Rightarrow F=m.a

also

F\propto \frac{1}{dt}

so, more the time, lesser the force.

<em>& </em><u><em>Impulse:</em></u>

I=F.dt

I=m.a.dt

I=m.\frac{dv}{dt}.dt

I=m.dv=dp

∵Initial velocity and final velocity(=0), of a certain mass is same irrespective of the stopping method.

So, the impulse in both the cases will be same.

4 0
3 years ago
Ca anyone help me with writing a lab report about the reaction between the pepper and the soap in water
7nadin3 [17]

Answer:

Buoyancy force and surface tension are the reactions that take places between soap and pepper experiment.

Explanation:

Surface tension:

The surface tension of a liquid is the tendency of liquid surfaces to resist an external force due to the cohesive nature of its molecules.

The pepper and soap experiment helps you to understand buoyancy force and surface tension.

Reaction between the pepper and soap is as following.

  • The pepper flakes float because of buoyancy force. It makes the pepper flakes to move away to the edge of the plate.
  • This happens because the liquid dish soap changes the surface tension of water.
  • And The pepper flakes are so light, it floats on the water surface due to surface tension.
  • when we add soap, it breaks the surface tension of water, but the water resists it. So they pull away from the soap along with the pepper flakes.
  • This pushes the pepper away from your soap covered finger.

This is the reaction that take places between soap and pepper experiment.

Learn more about Pepper and soap experiment here:

<u>brainly.com/question/9614070</u>

<u>#SPJ4</u>

6 0
2 years ago
The drawings show three charges that have the same magnitude but may have different signs. In all cases the distance d between t
Radda [10]

Answer:

a)F = 6816.5680 N

b) F' = 0 N

c)F''=28195.5N

Explanation:

Magnitude of charges M=1.6\muC

Distance d=2.6

Generally the equation for  Net Force is mathematically given by

For First Drawing

F =\frac{ k q^2}{d^2}+\frac{k q^2}{d^2}  

F =\frac{2* 9*10^9* (1.6*10^-6)^2}{ (2.6*10^-3^2}

F = 6816.5680 N

For second Drawing

F' =\frac{ k q^2}{d^2 }-\frac{ k q^2}{ d^2}  

F' = 0 N

For Third Drawing

F'' =\frac{ k q^2}{d^2} * \sqrt (2)

F'' = 9*10^9* (6.4*10^-6)^2 * \frac{\sqrt(2)}{(4.3*10^-3)^2}

F''=28195.5N

4 0
3 years ago
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