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3 years ago

5

I need help with the last question

2 answers:

TEA [102]3 years ago

4 0

The best object shows the Earth appearing is something that round and smooth.

Mariana [72]3 years ago

3 0

The best object to show the Earth's true appearance is something round and smooth. Since the earth is only slightly oblate, it doesn't matter based on its size, and you would use a pool ball as the perfect scale model, because it is very round and smooth.

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In the lab, You have a highly reactive metal like sodium. It is so reactive that water sets it off. How would you store it?

kenny6666 [7]

Answer:

Sodium is stored under paraffin oil

Explanation:

Group 1 metals are known to be very highly reactive. The chemical reactivity of the members of the group decreases down the group.

Sodium reacts violently with water and upon exposure to the atmosphere. As a result of this, it must be stored under paraffin oil.

8 0

3 years ago

List two things you should not do when encountering a funeral procession?

34kurt

party and being happy..........

7 0

3 years ago

A machine part has the shape of a solid uniform sphere of mass 250 g and a diameter of 4.30 cm. It is spinning about a frictionl

zysi [14]

Answer: $\alpha =9.302\ rad/s^2$

Explanation:

Given

mass of sphere $m=250\ gm$

diameter of sphere $d=4.30\ cm$

radius $r=\frac{4.30}{2}\ cm$

$f=0.0200\ N$

friction will provide resisting torque so

$f\times r=I\times \alpha$

where $I=\text{moment of Inertia}$

$f=\text{friction force}$

$\alpha =\text{angular acceleration}$

$I=\frac{2}{5}mr^2$

$0.02\times r=\frac{2}{5}mr^2\times \alpha$

$\alpha =\frac{5}{2r}\times f$

$\alpha =\frac{5}{2}\times \frac{2}{4.3\times 10^{-2}}\times 0.02$

$\alpha =9.302\ rad/s^2$

(b)time taken to decrease its rotational speed by $21\ rad/s$

$t=\dfrac{\Delta \omega }{\alpha }$

$t=\dfrac{21}{9.302}$

$t=2.25\ s$

6 0

3 years ago

If a m = 74.7 kg m=74.7 kg person were traveling at v = 0.800 c v=0.800c , where c c is the speed of light, what would be the ra

igomit [66]

Answer:

$\frac{E}{E_c} =3.125$

Explanation:

The kinetic energy of a rigid body that travels at a speed v is given by the expression:

$E_c=\frac{1}{2} mv^2$

The equivalence between mass and energy established by the theory of relativity is given by:

$E=mc^2$

This formula states that the equivalent energy $E$ can be calculated as the mass $m$ multiplied by the speed of light $c$ squared.

Where $c$ is approximately $3\times 10^{8} m/s$

Hence:

$E_c=\frac{1}{2} (74.7)*(0.8*3\times 10^{8} )^2=2.15136\times 10^{18} J$

$E=(74.7)*(3\times 10^{8} )^2 =6.723\times 10^{18} J$

Therefore, the ratio of the person's relativistic kinetic energy to the person's classical kinetic energy is:

$\frac{E}{E_c} =\frac{6.723\times 10^{18}}{2.15136\times 10^{18}} =3.125$

4 0

3 years ago

PLEASE How much voltage is required to run 1.6 A of current through a 2400 resistor? Use AV = IR.

sergey [27]

Explanation:

$from \: ohms \: law \\ voltage \: \: V =IR \\ = 1.6 \times 2400 \\ = 3840 \: Volts$

3 0

3 years ago