Hey does anyone know the answer?
2 answers:
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Complete Question
a car traveling at 28.4 m/s undergoes a constant deceleration of 1.92 m/s2 when the breaks are applied. How many revolutions does each tire make before the car comes to a stop? Assume that the car does not skid and that each tire has a radius of 0.307 m. Answer in units of rev.
Answer:
The value is
Explanation:
From the question we are told that
The speed of the car is
The constant deceleration experienced is
The radius of the tire is
Generally from kinematic equation we have that
Here v is the final velocity which is 0 m/s
So
=>
Generally the circumference of the tire is mathematically represented as
=>
=>
Generally the number of revolution is mathematically represented as
=>
=>
Answer:
the sphere
Explanation:
From the given information,
A free flow body diagrammatic expression for the small uniform disk and a small uniform sphere which are released simultaneously at the top of a high inclined plane can be seen in the image attached below.
From the diagram;
The Normal force mgsinθ - Friction force F = mass m × acceleration a
Meanwhile; the frictional force
where
in a rolling motion
Then;
∴
The Normal force mgsinθ - F = m × a can be re-written as:
making a the subject of the formula, we have:
Similarly;
I = mk² in which k is the radius of gyration
∴
replacing I = mk² into the above equation , we have:
where;
the uniform disk
the uniform sphere
∴
We can now see that the uniform sphere is greater than the disk as such the sphere will reach the bottom first.
