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3 years ago

Lolz help meeeeeeeeeeeeee

Physics

2 answers:

earnstyle [38]3 years ago

8 0

Answer: the first is gravity

the second is Newton’s 3rd Law of Motion

Hope this helped :)

Explanation:

garri49 [273]3 years ago

3 0

The first one is gravity

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The center of a moon of mass m is a distance D from the center of a planet of mass M. At some distance x from the center of the

Evgen [1.6K]

Question Continuation

Derive an expression for x in terms of m, M, and D. b) If the net force is zero a distance ⅔D from the planet, what is the ratio R of the mass of the planet to the mass of the moon, M/m?

Answer:

a. x = (D√M/m)/(√M/m + 1)

b. The ratio R of the mass of the planet to the mass of the moon=4:1

Explanation:

Given

m = Mass of moon

M = Mass of the planet

D = Distance between the centre of the planet and the moon

Net force = 0

Let Y be a point at distance x from the planet

Let mo = mass at point Y

Derive an expression for x in terms of m, M and D.

Formula for Gravitational Force is

F = Gm1m2/r²

Y = D - x

Force on rest mass due to mass M (FM) =Force applied on rest mass due to m (Fm)

FM = G * mo * M/x²

Fm = G * mo * m/Y²

Fm = G * mo * m/(D - x)²

FM = Fm = 0 ------ from the question

So,

G * mo * M/x² = G * mo * m/(D - x)² ----- divide both sides by G * mo

M/x² = m/(D - x)² --- Cross Multiply

M * (D - x)² = m * x²

M/m = x²/(D - x)² ---_ Find square roots of both sides

√(M/m) = x/(D - x) ----- Multiply both sides by (D - x)

(D - x)√(M/m) = x

D√(M/m) - x√(M/m) = x

D√(M/m) = x√(M/m) + x

D√(M/m) = x(√(M/m) + 1) ------- Divide both sides by √M/m + 1

x = (D√M/m)/(√M/m + 1)

b. Here x = ⅔D

FM = G * mo * M/x²

Fm = G * mo * m/(D - x)²

FM = Fm

G * mo * M/x² = G * mo * m/(D - x)² ----- divide both sides by G * mo

M/x² = m/(D - x)² --- (Substitute ⅔D for x)

M/(⅔D)² = m/(D - ⅔D)²

M/(4D/9) = m/(⅓D)²

9M/4D = m/(D/9)

9M/4D = 9m/D ---- Divide both side by 9/D

M/4 = m

M = 4m

M/m = 4

M:m = 4:1

So, the ratio R of the mass of the planet to the mass of the moon=4:1

3 0

3 years ago

At which point is the water table closest to the surface? Explain.

dangina [55]

The point is the water table closest to the surface in valleys.

In areas of topographic relief, the water table generally follows the surface but tends to approach it in valleys and intersect the surface with streams and lakes. Closest to the surface is the vented zone where the interstices between the soil are filled with both air and water. Below this layer is a saturation zone where the gaps are filled with water.

The water table is the subsurface boundary between the soil surface and the area where groundwater saturates the space between sediment and rock fissures. At this boundary, water pressure equals atmospheric pressure. The top surface of the groundwater is the groundwater table. Beneath this surface, all pore spaces and cracks in sediments and rocks are completely filled and saturated with water. Groundwater occurs in these saturated layers known as saturation zones or water vapor zones.

Learn more about The water table here:-brainly.com/question/1362512

#SPJ1

7 0

2 years ago

A 67 kg kg driver gets into an empty taptap to start the day's work. The springs compress 2.3×10−2 m m . What is the effective s

amid [387]

Point of correction, spring constant is 2.3×10−2 m not 2.3×10−2 m m

Answer:

28577 N/m

Explanation:

From Hooke's law, F=kx where F is force applied, k is spring constant and x is compression

F=mg=67*9.81

$k=\frac {mg}{x}$

$k=\frac {67*9.81}{2.3\times 10^{-2}}=28576.95652 N/m$

Approximately, 28577 N/m

8 0

3 years ago

A man pushes down on a table. what does the table do to the man?

solong [7]

Question: A man pushes down on a table. what does the table do to the man?

Answer: pushes back against the hand

Explanation: The weight of the ma pushes down on the table with a force mg while the table pushes up on the book with an equal and opposite force

question answered by

(jacemorris04)

3 0

3 years ago

Read 2 more answers

On the decibel scale, a “quiet whisper 1 meter away” is about ____________ decibels, where a “jackhammer 3 meters away” is ____

prisoha [69]

Looking at decibel scale tables on internet, a "quiet whisper 1 meter away" is generally reported to have a sound intensity of about 20 dB, while a jackhammer 3 meters away produces a sound of about 100 dB of intensity, so option a) could be the correct one.
However, the other options could be considered correct as well, because without knowing the exact sound power produced by the whisper or by the jackhammer it's impossible to calculate the exact sound intensity with precision, and since the values reported in the three options are very similar, all the three of them can be considered as valid.

5 0

4 years ago