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damaskus [11]
3 years ago
9

he equation of a line is y=2/3 x + 5. What is an equation of the line that is perpendicular to the given line and that passes th

rough the point (4,2)?
Mathematics
1 answer:
Levart [38]3 years ago
5 0
2/3 × m2 = - 1
m2 = - 3/2

2 = - 3/2(4) + c
4 = - 12 + 2c
2c = 16
c = 8
y = - 3/2x + 8
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3 0
3 years ago
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olga nikolaevna [1]

Answer:

y = x+2

Step-by-step explanation:

(x1,y1) is (-4,-2) and (x2,y2) is (2,4)

Slope intercept form is y = mx+b

m = slope

b = add on

Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Substitute numbers

Slope = \frac{4-(-2)}{2-(-4)}

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Simplify

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We can substitute y, x, and the slope

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Hope this helps :)

6 0
2 years ago
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melisa1 [442]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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