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ivann1987 [24]
3 years ago
15

A major source of today's medicines

Chemistry
1 answer:
Arada [10]3 years ago
5 0
A major source is coal
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Which phrase describes radiation?
stepan [7]

Answer:

The process in which energy is emitted by one object ,transmitted through .......

3 0
3 years ago
Why is phenolphthalein not a good indicator to use for a titration that has a ph of 6.0 at the equivalence point?
vekshin1
Phenolphthalein is not a good indicator to use for a titration for a solution that has a ph of 6.0 at the equivalence point because the color change of the solution at this pH level is not sharp. It changes the color of the solution to pink starting from pH 8.3 to 10. A pH level lower than 8.3  would only show a colorless solution. Thus, you would not be able to distinguish whether the solution has reached its equivalence point at pH 6.0. It is best to use this indicator for a system that is using a strong base titrated with a weak acid.
5 0
3 years ago
How does the structure of each passage help determine the content of the passage?
nadya68 [22]

The answer to the question is a. Passage I contains a character study, but Passage 2 focuses more on concepts.

for all who were wondering

4 0
3 years ago
Calculate the solubility of silver oxalate, ag2c2o4, in pure water. ksp = 1.0 × 10-11
aksik [14]
Answer is: the solubility of silver oxalate is <span>a. 1.4 × 10-4 m.
</span>

<span>Chemical reaction (dissociation) of silver oxalate in water: 
Ag</span>₂C₂O₄(s) → 2Ag⁺(aq) + C₂O₄²⁻<span>(aq).
Ksp(Ag</span>₂C₂O₄) = [Ag⁺]²·[C₂O₄²⁻<span>].
[C</span>₂O₄²⁻] = x; solubility of oxalate ion.

[Ag⁺] = 2[C₂O₄²⁻<span>] = 2x
1.0·10</span>⁻¹¹ = (2x)² · x = 4x³.

x = ∛1.0·10⁻¹¹ ÷ 4.

x = 1.4·10⁻⁴ M.

6 0
3 years ago
Given the following equation:
Anna [14]

Mass of KMnO4 required : 31.607 g

<h3>Further explanation </h3>

The reaction equation is the chemical formula of reagents and product substances  

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products  

Reaction

2KMnO₄ → K₂MnO₄ + MnO₂ + O₂

mol of O₂ :

\tt \dfrac{1.6}{16}=0.1

mol ratio KMnO₄ : O₂ = 2 : 1

mol of KMnO₄ :

\tt \dfrac{2}{1}\times 0.1=0.2

mass of KMnO₄ :

MW KMnO₄ : 158,034 g/mol

\tt mass=0.2\times 158,034 =31.607~g

4 0
3 years ago
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